<h2>Answer is option "E"</h2>
Explanation:
- Enzymes belong to the proteins category because enzymes are long chains of amino acids bound together by peptide bonds
- Enzymes have a special marker on them called an active site that, like a puzzle piece, fits with only one other type of molecule, generally referred to as a substrate. The substrate is a molecule that will undergo a reaction that results in it splitting into two separate molecules, called products
- The substrate-specific to a particular enzyme will bind at the active site, forming what is known as an enzyme/substrate complex. In other words, a complex formed by the union of the enzyme and substrate
- Hence, the right answer is option E "both A and B"
1. Whether or not height affects running speed.
2. She and her friend Melissa exercised equal amounts, but Melissa still ran faster, so Sally wanted to know why.
3. speed
4. quantitative
5. males vs female data, so gender, and how much each test subject exercises, so their athleticism
6. Gender, distance ran
7. no
8. 1 trial as a class, but independent data for each student, so I would say there were as many trials as students in the class
<span>"Cytoplasmic determinates" are the proteins and rnas which perform a greatly significant role of vital importance in oocyte maturation, essential to organ formation of an organism's development very early on in the process which takes place in the mother's ovary.</span>
Q1. <span>What is the mass of 1 cup of water and 2 teaspoons of salt?
The answer is 258 g.
Density (D) is mass (m) divided by volume (V): D = m/V
So, m = D * V
According to the US units, the volume of 1 cup is: V = 236.6 cm</span>³.
The density of the water is: D = 1 g/cm³.
So, the mass of 1 cup of water is: m = 1 g/cm³ * 236.6 cm³ = 236.6 g.
According to the US units, the volume of 1 teaspoon is: V = 4.93 cm³.
The density of salt is: D = 2.17 g/cm³.
So, the mass of 1 teaspoon of salt is: m = 2.17 g/cm³ * 4.93 cm³ = 10.7 g.
The mass of 1 cup of water and 2 teaspoons of salt is
236.6 g + 2 * 10.7 g = 236.6 g + 21.4 g = 258 g.
Q2. <span>What is the density of 1 cup of water and 2 teaspoons of salt?
</span>The answer is 3.17 g/cm³.
Density (D) is mass (m) divided by volume (V): D = m/V
According to the US units, the volume of 1 cup is: V = 236.6 cm³.
The mass of 1 cup of water from question 1 is: m = 236.6 g.
So, the density of 1 cup of water is: D = 236.6 g / 236.6 cm³ = 1 g/cm³
According to the US units, the volume of 1 teaspoon is 4.93 cm³. The volume of 2 teaspoons is: V = 2 * 4.93 cm³ = 9.86 cm³.
The mass of 1 teaspoon of salt from question 1 is: m = 10.7 g. The mass of 2 teaspoons of salt is: m = 2 * 10.7 g = 21.4 g.
So, the density of 2 teaspoons of salt is: D = 21.4 g / 9.86 cm³ = 2.17 g/cm³
The density of 1 cup of water and 2 teaspoons of salt is:
1 g/cm³ + 2.17 g/cm³ = 3.17 g/cm³
Q3. <span>What is the mass of 1 cup of water and 3 teaspoons of salt?
The answer is 268.7 g.
</span>Density (D) is mass (m) divided by volume (V): D = m/V
So, m = D * V
According to the US units, the volume of 1 cup is: V = 236.6 cm³.
The density of the water is: D = 1 g/cm³.
So, the mass of 1 cup of water is: m = 1 g/cm³ * 236.6 cm³ = 236.6 g.
According to the US units, the volume of 1 teaspoon is: V = 4.93 cm³.
The density of salt is: D = 2.17 g/cm³.
So, the mass of 1 teaspoon of salt is: m = 2.17 g/cm³ * 4.93 cm³ = 10.7 g.
The mass of 1 cup of water and 3 teaspoons of salt is
236.6 g + 3 * 10.7 g = 236.6 g + 32.1 g = 268.7 g.
Q4. <span>What is the density of 1 cup of water and 3 teaspoons of salt?
The answer is 3.17 g/cm</span>³<span>
</span>Density (D) is mass (m) divided by volume (V): D = m/V
According to the US units, the volume of 1 cup is: V = 236.6 cm³.
The mass of 1 cup of water from question 1 is: m = 236.6 g.
So, the density of 1 cup of water is: D = 236.6 g / 236.6 cm³ = 1 g/cm³
According to the US units, the volume of 1 teaspoon is 4.93 cm³. The volume of 3 teaspoons is: V = 3 * 4.93 cm³ = 14.79 cm³.
The mass of 1 teaspoon of salt from question 1 is: m = 10.7 g. The mass of 3 teaspoons of salt is: m = 3 * 10.7 g = 32.1 g.
So, the density of 3 teaspoons of salt is: D = 32.1 g / 14.79 cm³ = 2.17 g/cm³
The density of 1 cup of water and 3 teaspoons of salt is:
1 g/cm³ + 2.17 g/cm³ = 3.17 g/cm³
Q5. What is the mass of 1 cup of water and 4 teaspoons of salt?
The answer is 279.4 g.
Density (D) is mass (m) divided by volume (V): D = m/V
So, m = D * V
According to the US units, the volume of 1 cup is: V = 236.6 cm³.
The density of the water is: D = 1 g/cm³.
So, the mass of 1 cup of water is: m = 1 g/cm³ * 236.6 cm³ = 236.6 g.
According to the US units, the volume of 1 teaspoon is: V = 4.93 cm³.
The density of salt is: D = 2.17 g/cm³.
So, the mass of 1 teaspoon of salt is: m = 2.17 g/cm³ * 4.93 cm³ = 10.7 g.
The mass of 1 cup of water and 4 teaspoons of salt is
236.6 g + 4 * 10.7 g = 236.6 g + 42.8 g = 279.4 g.
Q6. What is the density of 1 cup of water and 4 teaspoons of salt?
The answer is 3.17 g/cm³
Density (D) is mass (m) divided by volume (V): D = m/V
According to the US units, the volume of 1 cup is: V = 236.6 cm³.
The mass of 1 cup of water from question 1 is: m = 236.6 g.
So, the density of 1 cup of water is: D = 236.6 g / 236.6 cm³ = 1 g/cm³
According to the US units, the volume of 1 teaspoon is 4.93 cm³. The volume of 4 teaspoons is: V = 4 * 4.93 cm³ = 19.72 cm³.
The mass of 1 teaspoon of salt from question 1 is: m = 10.7 g. The mass of 4 teaspoons of salt is: m = 4 * 10.7 g = 42.8 g.
So, the density of 3 teaspoons of salt is: D = 42.8 g / 19.72 cm³ = 2.17 g/cm³
The density of 1 cup of water and 4 teaspoons of salt is:
1 g/cm³ + 2.17 g/cm³ = 3.17 g/cm³
Answer:
False, the endocrine system sends hormones not nerve impulses