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faltersainse [42]
2 years ago
12

Which is the rate of change for the interval between -6 and -3 on the x axis

Mathematics
2 answers:
Oliga [24]2 years ago
9 0

Answer:

-2 on edge

Step-by-step explanation:

kondor19780726 [428]2 years ago
7 0

Answer:-2

Step-by-step explanation:

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The mailing list of an agency that markets scuba-diving trips to the Florida Keys contains 78% males and 22% females. The agency
choli [55]

Answer:

a) 0.98% probability that 17 of the 29 people are men.

b) 3.86% probability that the first woman is reached on the 8th call

Step-by-step explanation:

For each person chosen by the agency, there are only two possible outcomes. Either it is a man, or it is a woman. The probability of selecting a man or a women in each trial is independent from other trials. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

(a) What is the probability that 17 of the 29 people are men?

This is P(X = 17) when n = 29, p = 0.78. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 17) = C_{29,17}.(0.78)^{17}.(0.22)^{12} = 0.0098

0.98% probability that 17 of the 29 people are men.

(b) What is the probability that the first woman is reached on the 8th call?

On the first 7 trials, all men, each with a 78% probability.

On the 8th trial, a women, with a 22% probability. So

P = (0.78)^{7}*0.22 = 0.0386

3.86% probability that the first woman is reached on the 8th call

4 0
3 years ago
Urn A has balls numbered 1 through 6. Urn B has balls numbered 1 through 4. What is the probability that a 4 is drawn from A fol
oksian1 [2.3K]
Drawing the tree diagram of the problem, we see that there are 6 branches for drawing from Urn A, and then 4 branches for each of the 6 branches, for drawing from Urn B.

This means that there are 6*4=24 possible outcomes, which could be listed as
{(1, 1), (1, 2), (1, 3), (1, 4), (2, 1)... (6, 3), (6, 4)},

where the first coordinates represent drawing from urn A, and the second coordinates, drawing from urn B.

(4, 2) is one of these 24, so the probability is 1/24


remark, this problem could also have been solved by the multiplication principle of the probabilities of separate events, that is 1/6 (probability of drawing 4 from Urn A) times 1/4 (probability of drawing 2 from B) = 1/24


Answer: 1/24

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What is the middle term of the product of (5a - 7)(2a - 1)?
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(5a-7) (2a-1) = -19a
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