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3 years ago

Find the zeros of the polynomial function.

1 answer:

8 0

◆ QUADRATIC EQUATIONS ◆

$given \: equation \: is \: , \\ \\ {x}^{2} - 12x + 20 = 0 \\ \\ using \: quadratic \: formula \: , \\ \\ x = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \: \: \: \: = \frac{ - ( - 12) + \sqrt{ { (- 12)}^{2} - 4(1)(20) } }{2(1)} \\ \\ x = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \: \: \: \: = \frac{ - ( - 12) - \sqrt{ { (- 12)}^{2} - 4(1)(20) } }{2(1)} \\ \\ x = \frac{12 + 8}{2} \: \: \: \: \: or \: \: \: \: x = \frac{12 - 8}{2} \\ \\ x = 10 \: \: \: \: \: or \: \: \: \: \: x = 2 \: \: \: ans.$

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Which expression is equivalent to the expression (7×2)^7

ddd [48]

Answer:

9^7

Step-by-step explanation:

7*2=9

7 0

3 years ago

Find the minimum product of two numbers whose difference is 17. <br> what are the numbers?

Marysya12 [62]

A number is an arithmetic value that is used to represent a quantity and calculate it. The two numbers will be 17 and 0, so the product of the two is minimal.

<h3>What are Numbers?</h3>

A number is an arithmetic value that is used to represent a quantity and calculate it. Numericals are written symbols that represent numbers, such as "3."

Given the difference between the two numbers is 17. Let the first number be zero, then the second number will be 17. Thus, the product of the two numbers will be 0, which is the minimum.

If the first number is further increased such as 1, then the other number will be 18, and the product of the two will be 18, which is greater than zero.

Hence, the two numbers will be 17 and 0, so the product of the two is minimal.

Learn more about Numbers:

brainly.com/question/17429689

#SPJ1

7 0

2 years ago

-2(3y+5)=-4, find the value of 5y

Inessa05 [86]

Y=64 that's the answer to the problem

3 0

3 years ago

Read 2 more answers

Determine whether the system of linear equations has one and only one solution, infinitely many solutions, or no solution.

Len [333]

Answer:

only one solution

Step-by-step explanation:

Complete question:

<em>Determine whether the system of linear equations has one and only one solution, infinitely many solutions, or no solution. 2x − y = 2 3x + y = −6 one and only one solution infinitely many solutions no solution Find the solution, if one exists. (If there are infinitely many solutions, express x and y in terms of the parameter t. If there is no solution, enter NO SOLUTION.) (x, y) </em>=

Given the expression

2x − y = 2 .... 1

3x + y = −6 ..... 2

We are to determine the number of solution the equation has:

Add equation 1 and 2

2x + 3x = 2 - 6

5x = -4

x = -4/5

Substitute x = -4/5 into 1

From 1: 2x − y = 2 .... 1

2(-4/5) - y = 2

-8/5 - y = -2

-y = -2+8/5

-y = -10+8/5

-y = -2/5

y = 2/5

<em>Since the value of x and y are just 1 hence the system of equations has ine solution</em>

3 0

2 years ago

Complete the proof please. A. SAS B. ASA C. AAS D.HL

riadik2000 [5.3K]

Option B:

ASA congruence

Solution:

Step 1: Given

$\overline{Q S} \perp \overline{Q T}$

Step 2: Given

$\overline{R T} \perp \overline{R S}$

Step 3: Given

$\overline{Q U} \cong \overline{R U}$ (Included side)

Step 4: All right angles are congruent.

$\angle Q \cong \angle R$ (Angle)

Step 5: By vertical angle theorem

$\angle Q U T \cong \angle R U S$ (Angle)

Step 6: By ASA congruence

QU and RU are included side of corresponding angles.

Therefore by ASA congruence rule,

$\Delta Q T U \cong \Delta R S U$

Option B is the correct answer.

Hence proved.

6 0

3 years ago