It is 6 units because you find the absolute value of the two different coordinates, in this case it is 4 and -2. Since they belong in different quadrants (one x or y value is positive and the other is negative) you add them. If they are both in the same quadrant, you subtract them.
Answer:
Step-by-step explanation:
Our inequality is |125-u| ≤ 30. Let's separate this into two. Assuming that (125-u) is positive, we have 125-u ≤ 30, and if we assume that it's negative, we'd have -(125-u)≤30, or u-125≤30.
Therefore, we now have two inequalities to solve for:
125-u ≤ 30
u-125≤30
For the first one, we can subtract 125 and add u to both sides, resulting in
0 ≤ u-95, or 95≤u. Therefore, that is our first inequality.
The second one can be figured out by adding 125 to both sides, so u ≤ 155.
Remember that we took these two inequalities from an absolute value -- as a result, they BOTH must be true in order for the original inequality to be true. Therefore,
u ≥ 95
and
u ≤ 155
combine to be
95 ≤ u ≤ 155, or the 4th option
Answer: b. 30%
Step-by-step explanation:
given data:
population size (n) = 100
A1 = 0.7
A2 = 0.3
if A1 and A2 are selectively neutral, the probability that A2 would drift to fixation
= 0.3
= 30%
there is a. 30% chance that A2 would drift towards fixation.
Answer:
Solution given:
Cos -θ:
since cos -θ=Cos θ
Cos θ :
=:
b=
h=4
p==
So
Sin θ==
So third one is a required answer.