L = 3 + 2w
119 = w × ( 3 + 2w )
119 = 3w + 2w^2
2w^2 + 3w - 119 = 0
( w - 7 ) ( 2w + 11 ) = 0
w = 7
x = w
x = 7
Zeroes:
We must solve

To do so, we define the auxiliary variable
. The equation becomes

The quadratic formula yields the solutions

Substituting back
gives

So, the zeroes are -6, -3, 3, 6.
Turning points:
Turning points are points where a function stops being increasing to become decreasing, or vice versa. Since functions are increasing when their first derivative is positive and decreasing when it's negative, turning points are points where the first derivative is zero.
We have

If we set the derivative to be zero, we have

So, the derivative is zero if x=0 or

You'll actually need to graph for the first segment
but the second part can be solved with algebra
The equation of the line is y(x)=-x
if we test the co0ordinates we can find if the point lies on the line
(5,5)
y(x)=-x
Using the x co-ordinate
y(5)= -5
y=-5
Leaving us with (5,-5)
Because (5,-5) is not (5,5)
This is not a point on the line
The slope of the line is -1
Answer:20
Step-by-step explanation:
17 + 3 = 20
20 + 3 = 23