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Oksana_A [137]
2 years ago
6

number of bald eagles in a country a discrete random​ variable, a continuous random​ variable, or not a random​ variable?

Mathematics
1 answer:
kykrilka [37]2 years ago
7 0

Answer:

Discrete random variable.

Step-by-step explanation:

Discrete variable:

Countable numbers(0,1,2,3,...)

Continuous variable:

Can assume decimal values, such as 0.5, 2.5,...

Number of bald eagles:

Number of bald eagles is a countable value, either there a 0, 100, 1000,... so it is a discrete random variable.

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Solve the compound inequality |3x-9|≤15 and |2x-3|≥5. Give answer in interval notation.
laila [671]

Answer:

The solution of |3x-9|≤15 is [-2;8] and the solution |2x-3|≥5 of is  (-∞,2] ∪ [8,∞)

Step-by-step explanation:

When solving absolute value inequalities, there are two cases to consider.

Case 1: The expression within the absolute value symbols is positive.

Case 2: The expression within the absolute value symbols is negative.

The solution is the intersection of the solutions of these two cases.

In other words, for any real numbers a and b,

  • if |a|> b then a>b or a<-b
  • if |a|< b then a<b or a>-b

So, being |3x-9|≤15

Solving: 3x-9 ≤ 15

3x ≤15 + 9

3x ≤24

x ≤24÷3

x≤8

or 3x-9 ≥ -15

3x ≥-15 +9

3x ≥-6

x ≥ (-6)÷3

x ≥ -2

The solution is made up of all the intervals that make the inequality true. Expressing the solution as an interval: [-2;8]

So, being |2x-3|≥5

Solving: 2x-3 ≥ 5

2x ≥ 5 + 3

2x ≥8

x ≥8÷2

x≥8

or 2x-3 ≤ -5

2x ≤-5 +3

2x ≤-2

x ≤ (-2)÷2

x ≤ -2

Expressing the solution as an interval: (-∞,2] ∪ [8,∞)

6 0
3 years ago
A normally distributed population has mean 57,800 and standard deviation 750. Find the probability that a single randomly select
Stels [109]

Answer:

(a) Probability that a single randomly selected element X of the population is between 57,000 and 58,000 = 0.46411

(b) Probability that the mean of a sample of size 100 drawn from this population is between 57,000 and 58,000 = 0.99621

Step-by-step explanation:

We are given that a normally distributed population has mean 57,800 and standard deviation 75, i.e.; \mu = 57,800  and  \sigma = 750.

Let X = randomly selected element of the population

The z probability is given by;

           Z = \frac{X-\mu}{\sigma} ~ N(0,1)  

(a) So, P(57,000 <= X <= 58,000) = P(X <= 58,000) - P(X < 57,000)

P(X <= 58,000) = P( \frac{X-\mu}{\sigma} <= \frac{58000-57800}{750} ) = P(Z <= 0.27) = 0.60642

P(X < 57000) = P( \frac{X-\mu}{\sigma} < \frac{57000-57800}{750} ) = P(Z < -1.07) = 1 - P(Z <= 1.07)

                                                          = 1 - 0.85769 = 0.14231

Therefore, P(31 < X < 40) = 0.60642 - 0.14231 = 0.46411 .

(b) Now, we are given sample of size, n = 100

So, Mean of X, X bar = 57,800 same as before

But standard deviation of X, s = \frac{\sigma}{\sqrt{n} } = \frac{750}{\sqrt{100} } = 75

The z probability is given by;

           Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)  

Now, probability that the mean of a sample of size 100 drawn from this population is between 57,000 and 58,000 = P(57,000 < X bar < 58,000)

P(57,000 <= X bar <= 58,000) = P(X bar <= 58,000) - P(X bar < 57,000)

P(X bar <= 58,000) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{58000-57800}{\frac{750}{\sqrt{100} } } ) = P(Z <= 2.67) = 0.99621

P(X < 57000) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{57000-57800}{\frac{750}{\sqrt{100} } } ) = P(Z < -10.67) = P(Z > 10.67)

This probability is that much small that it is very close to 0

Therefore, P(57,000 < X bar < 58,000) = 0.99621 - 0 = 0.99621 .

7 0
3 years ago
Which of the following expressions are equivalent to -45+12
meriva

Answer:

-45 + 12 is equal to -33

and <u>Choice A </u> is also equal to -33.

Step-by-step explanation:

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2 years ago
PLEASE HELP ILL GIVE U BRAINLEST PLUS 50 POINTS IF U GET IT RIGHT
timama [110]

Answer:

{x}^{2}  + 17x + 3

Step-by-step explanation:

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7 0
3 years ago
The table shows the input and output of a function Table(input:3,4,6,11. Output:5,7,11,21) write an equation, in function nation
Anni [7]

f(x) = 2x - 1

To obtain a function we require values of x for x = 3, 4, 5 , 6, .....

The output appears to increase in steps of 2

3 → 5

4 → 7

5 → 9

6 → 11

Looking at the consecutive values of y we should see that these are twice the corresponding value of x subtract 1

f(x) = 2x - 1 ← is a possible function

checking the values for x in the input


f(3) =(2 × 3 ) - 1 = 5

f(4) = (2 × 4 ) - 1 = 7

f(6) = (2 × 6 ) - 1 = 11

f(11) = (2 × 11 ) - 1 = 21




6 0
3 years ago
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