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2 years ago

number of bald eagles in a country a discrete random variable, a continuous random variable, or not a random variable?

Mathematics

1 answer:

kykrilka [37]2 years ago

7 0

Answer:

Discrete random variable.

Step-by-step explanation:

Discrete variable:

Countable numbers(0,1,2,3,...)

Continuous variable:

Can assume decimal values, such as 0.5, 2.5,...

Number of bald eagles:

Number of bald eagles is a countable value, either there a 0, 100, 1000,... so it is a discrete random variable.

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A beach ball has a mass of 5 g and a volume of 20 cm3. What is the object's density? A. 4 g/cm3 B. 100 g/cm3 C. 0.25 D. g/cm3 4

Triss [41]

<h2>Hello!</h2>

The answer is:

C. $0.25\frac{g}{cm^{3} }$

The density is the relation between the mass and the volume of an object. We are given four options to chose, and we can find the correct one by doing the following calculations:

$Density=\frac{mass}{volume}=\frac{5g}{20cm^{3}}=0.25\frac{g}{cm^{3}}$

So, the correct options is C. $0.25\frac{g}{cm^{3} }$

Have a nice day!

7 0

3 years ago

Read 2 more answers

when 6 is subtracted from the square of a number, the result is 5 times the number. Find the negative solution.

sveta [45]

When 6 is subtracted from the square of a number, the result is 5 times the number, then the negative solution is -1

<h3><u>Solution:</u></h3>

Given that when 6 is subtracted from the square of a number, the result is 5 times the number

To find: negative solution

Let "a" be the unknown number

Let us analyse the given sentence

square of a number = $a^2$

6 is subtracted from the square of a number = $a^2 - 6$

5 times the number = $5 \times a$

<em><u>So we can frame a equation as:</u></em>

6 is subtracted from the square of a number = 5 times the number

$a^2 - 6 = 5 \times a\\\\a^2 -6 -5a = 0\\\\a^2 -5a -6 = 0$

<em><u>Let us solve the above quadratic equation</u></em>

For a quadratic equation $ax^2 + bx + c = 0$ where $a \neq 0$

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here in this problem,

$a^2-5 a-6=0 \text { we have } a=1 \text { and } b=-5 \text { and } c=-6$

Substituting the values in above quadratic formula, we get

$\begin{array}{l}{a=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(-6)}}{2 \times 1}} \\\\ {a=\frac{5 \pm \sqrt{25+16}}{2}=\frac{5 \pm \sqrt{49}}{2}} \\\\ {a=\frac{5 \pm 7}{2}}\end{array}$

We have two solutions for "a"

$\begin{array}{l}{a=\frac{5+7}{2} \text { and } a=\frac{5-7}{2}} \\\\ {a=\frac{12}{2} \text { and } a=\frac{-2}{2}}\end{array}$

We have asked negative solution. So a = -1

Thus the negative solution is -1

6 0

3 years ago

Given that rectangle MNOP~ rectangle STUV~, what is the length of ___<br> TU

IrinaK [193]

A parallelogram in which adjacent sides are perpendicular to each other is called a rectangle. The value of x or the length of TU is 22.5.

<h3>What is a rectangle?</h3>

That parallelogram in which adjacent sides are perpendicular to each other is called a rectangle. A rectangle is always a parallelogram and a quadrilateral but the reverse statement may or may not be true.

Since all the rectangles are similar, therefore, the corresponding sides of the rectangle will be in ratio. Therefore,

$\dfrac{\text{Length of STUV}}{\text{Length of MNOP}} = \dfrac{9}{6}$

Similarly, the breadth will be,

$\dfrac{\text{Width of STUV}}{\text{Width of MNOP}} = \dfrac{\text{Length of STUV}}{\text{Length of MNOP}}\\\\\\\dfrac{\text{Width of STUV}}{\text{Width of MNOP}} = \dfrac{9}{6}\\\\\\\dfrac{x}{15}=\dfrac96\\\\\\x = \dfrac{9 \times 15}{6} = 22.5$