Answer:
a.The phenotypic proportions obtained after having the genotypes are 50% marbled seeds, 25% spotted and dotted seeds since they are codominant, 25% spotted seeds.
b. Taking into account the F1 genotypes in the previous point, the expected phenotypes for the first crossing are 100% marbled seeds and for the second crossing 100% dotted seeds.
Explanation:
Let's suppose:
Marbled allele: M
Spotted allele: S
Dotted allele: D
Allele for Clear: C
a. Because both crosses were between homozygous parents, the entire F1 genotype is the same.
For the first crossing the descendants have the MS genotype, and for the second crossing the descendants have the DC genotype. It is enough to make a Punnett square to obtain the different combinations of genotypes between the crossing of MS and DC.
First one is A
Second one is B
Hope this helps !
Fimbriae is the word you're looking for
Answer/Explanation:
The replication of DNA is semi-conservative, as each new molecule of DNA inherits one of the parental strands each, and one new strand each. DNA is replicated using the enzyme DNA polymerase, which synthesises a new strand by adding nucleotides in a sequence through complementary base pairing with the template strand. This occurs before the mitosis stage of the cell cycle, where the cell divides. Before this cell division happens, the cell has to pass certain checkpoints controlled by enzymes which ensure environmental conditions are optimal for dividing, and that the new DNA is free from errors.
