Answer:
The area of the square adjacent to the third side of the triangle is 11 units²
Step-by-step explanation:
We are given the area of two squares, one being 33 units² the other 44 units². A square is present with all sides being equal, and hence the length of the square present with an area of 33 units² say, should be x² = 33 - if x = the length of one side. Let's make it so that this side belongs to the side of the triangle, to our convenience,
x² = 33,
x = 
.... this is the length of the square, but also a leg of the triangle. Let's calculate the length of the square present with an area of 44 units². This would also be the hypotenuse of the triangle.
x² = 44,
x = 
.... applying pythagorean theorem we should receive the length of a side of the unknown square area. By taking this length to the power of two, we can calculate the square's area, and hence get our solution.
Let x = the length of the side of the unknown square's area -
= 
+ 
,
x = 
... And squared is 11, making the area of this square 11 units².
Answer:
D
Step-by-step explanation:
Just took it.
Answer:
0.3*10+10/5
PEMDAS (left to right)
3+2
5
Step-by-step explanation:
Answer:
B 29 words/min
Step-by-step explanation:
I just put it into desmos and went to the third number line
We will use the proper formula and solve.
-> A diameter of 48 / 2 = 24 feet as our radius
Area:
A = πr²
A = (3.14)(24)²
A = 1,808.64 ft²
The circle has an area of about 1,808.64 ft²
Circumference:
C = 2πr
C = 2(3.14)(24)
C = 150.72 ft
The circle has a circumference of about 150.72 ft
