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Nonamiya [84]
3 years ago
6

2. In AGHK, GH = 11, HK = 21, and GK = 15. To the nearest tenth, what is m​

Mathematics
1 answer:
Simora [160]3 years ago
7 0

Answer:

ok here is the answer

Step-by-step explanation:

how about you stop cheating and do it by your self

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Answer:

1) The mean calculated for this case is \bar X=61.5

2)  61.5-5.4=56.1

3) 61.5+5.4=66.9

4) B. An interval estimate gives us a sense of the accuracy of the point estimate whereas a point estimate alone does not.

Because with the confidence interval we know the confidence level of the interval, and the limits for the parameter at some significance level.  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Part 1

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (a)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (b)  

The mean calculated for this case is \bar X=61.5

The sample deviation calculated s=5.143

\mu population mean (variable of interest)

n=6 represent the sample size  

Part 2

The confidence interval for the mean is given by the following formula:

\bar X \pm ME   (1)

So if we have the margin of error 5.4mm we can find the lowr limit like this:

61.5-5.4=56.1

Part 3

61.5+5.4=66.9

Part 4

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Because with the confidence interval we know the confidence level of the interval, and the limits for the parameter at some significance level.

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