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gayaneshka [121]
3 years ago
6

In the reaction C5H8 + ______ O2 --> 8H2O + 5CO2, what coefficient should be placed in front of O2 to balance the reaction?

Chemistry
2 answers:
Ne4ueva [31]3 years ago
7 0
C
9O2 --> 18 O

C5H8 + 9O2 --> 8H2O + 5CO2
sweet [91]3 years ago
7 0

Answer:

The answer is c

Explanation:

You might be interested in
A slice of Swiss cheese contains 41 mg of sodium.
larisa86 [58]

Answer:

a. 41 mg equals 0.041 grams.

b. 41 mg equals 0.0014462 ounces

c. 41 mg equals 9.039*10⁻⁵ pounds

Explanation:

You know that a slice of Swiss cheese contains 41 mg of sodium.

a. What is this mass in grams?

Knowing that 1 mg = 10⁻³ g, you can apply the following rule of three: if 1 mg equals 10⁻³ g or 0.001 grams, 41 mg will be equivalent to how much mass in g?

mass=\frac{41 mg*0.001 g}{1 mg}

mass= 0.041 grams

<u><em> 41 mg equals 0.041 grams.</em></u>

b. What is this mass in ounces?

Knowing that 1 mg = 3.5274 * 10⁻⁵ ounces, you can apply the following rule of three: if 1 mg equals 3.5274 * 10⁻⁵ ounces, 41 mg will be equivalent to how much mass in ounces?

mass=\frac{41 mg*3.5274*10^{-5}ounces }{1 mg}

mass= 1.4462*10 ⁻³ ounces= 0.0014462 ounces

<u><em>41 mg equals 0.0014462 ounces</em></u>

c. What is this mass in pounds?

Knowing that 1 mg = 2.20462 * 10⁻⁶ pounds, you can apply the following rule of three: if 1 mg equals 2.20462 * 10⁻⁶ pounds, 41 mg will be equivalent to how much mass in pounds?

mass=\frac{41 mg*2.20462*10^{-6}pounds }{1 mg}

mass= 9.039*10⁻⁵ pounds

<u><em>41 mg equals 9.039*10⁻⁵ pounds</em></u>

5 0
3 years ago
A tree is an example
zzz [600]
The answer is A it’s tall
8 0
3 years ago
What areas did japan invade in 1931 and 1937
Yanka [14]

Answer:

china

Explanation:

3 0
3 years ago
What are the coefficients for the reaction _Cl2O5 + _H2O → _HClO3 once it is balanced?
Artemon [7]
Cl2O5+H20-->2HClO3

Just remember to have the same number of each element on both sides of the equation.
5 0
3 years ago
When the following oxidation-reduction occurs, what is the balanced reduction half-reaction after the electrons in both half rea
Lostsunrise [7]

Answer :  The balanced reduction half-reaction is:

3Cu^{2+}+6e^-\rightarrow 3Cu

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

The given balanced redox reaction is :

Al(s)+Cu^{2+}(aq)\rightarrow Al^{3+}(aq)+Cu(s)

The half oxidation-reduction reactions are:

Oxidation reaction : Al\rightarrow Al^{3+}+3e^-

Reduction reaction : Cu^{2+}+2e^-\rightarrow Cu

In order to balance the electrons, we multiply the oxidation reaction by 2 and reduction reaction by 3 and then added both equation, we get the balanced redox reaction.

Oxidation reaction : 2Al\rightarrow 2Al^{3+}+6e^-

Reduction reaction : 3Cu^{2+}+6e^-\rightarrow 3Cu

The balanced redox reaction will be:

2Al(s)+3Cu^{2+}(aq)\rightarrow 2Al^{3+}(aq)+3Cu(s)

Thus, the balanced reduction half-reaction is:

3Cu^{2+}+6e^-\rightarrow 3Cu

6 0
3 years ago
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