It would be 50? your adding/increaseing 44.2 centimeters to 16 centimeters because
other leg = 12 cm
using Pythagoras' identity with x as the side to be found, then
x = √(13² - 5² ) = √(169 - 25 ) =√144 = 12
Problem
For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground
Solution
We know that the x coordinate of a quadratic function is given by:
Vx= -b/2a
And the y coordinate correspond to the maximum value of y.
Then the best options are C and D but the best option is:
D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a
The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.
