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2 years ago

13

(6th grade math) Jacob has to buy treats for his class he can buy 105 tootsie rolls and 35 lolly pops for $7.35 or he can by 35

tootsie rolls and 70 lolly pops for $11.20 how much do individual tootsie rolls and lolly pops cost

1 answer:

Semmy [17]2 years ago

3 0

Answer:

$0.02 for tootsie rolls and $0.15 for lolly pops

Step-by-step explanation:

105x+35y=7.35

35x+70y=11.20

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Answer:

1) Function h

interval [3, 5]

rate of change 6

2) Function f

interval [3, 6]

rate of change 8.33

3) Function g

interval [2, 3]

rate of change 9.6

Step-by-step explanation:

we know that

To find the average rate of change, we divide the change in the output value by the change in the input value

the average rate of change is equal to

$\frac{f(b)-f(a)}{b-a}$

step 1

Find the average rate of change of function h(x) over interval [3,5]

Looking at the third picture (table)

$f(a)=h(3)=4$

$f(b)=h(5)=16$

$a=3$

$b=5$

Substitute

$\frac{16-4}{5-3}=6$

step 2

Find the average rate of change of function f(x) over interval [3,6]

Looking at the graph

$f(a)=f(3)=10$

$f(b)=f(6)=35$

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$b=6$

Substitute

$\frac{35-10}{6-3}=8.33$

step 3

Find the average rate of change of function g(x) over interval [2,3]

we have

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$f(b)=g(3)=\frac{1}{5}(4)^3=\frac{64}{5}$

$a=2$

$b=3$

Substitute

$\frac{\frac{64}{5}-\frac{16}{5}}{3-2}=9.6$

therefore

In order from least to greatest according to their average rates of change over those intervals

1) Function h

interval [3, 5]

rate of change 6

2) Function f

interval [3, 6]

rate of change 8.33

3) Function g

interval [2, 3]

rate of change 9.6

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2 years ago

30% of number A is 10 more than 20% of number B. 30% of number B is 35 more than 20% of number A. Find the numbers A and B.

anygoal [31]

Answer:

A = 76.85

B =65.28

Step-by-step explanation:

(30/100)A = 10 + (20/100)B

0.3A - 0.2B = 10 ...... equation (i)

(30/100)B + 35 = (20/100)A

0.2A - 0.3B = 35 ........ equation (ii)

From equation (i)

0.3A = 10 - 0.2B

A = (10 - 0.2b) / 0.3

A = 33.33 - 0.67B ........equation (iii)

Put equation (iii) into equation (ii)

0.2(33.33 - 0.67B) - 0.3B = 35

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B = 28.33 / 0.434

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Put B = 65.28 into equation (i)

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0.3A - 0.2(65.28) = 10

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0.3A = 10 + 13.056

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