Answer:
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Step-by-step explanation:
jk im still working on qit
Answer:
x=3
Step-by-step explanation:
0=x-3
-x=-3
x=3
Answer:
0.3721 or 37.21%
Step-by-step explanation:
P(I) = 0.60; P(II) = 0.40;
P(not defective I) = 0.90; P(not defective II) = 0.80
The probability that the phone came from factory II, given that is not defective, is determined by the probability of a phone from factory II not being defective divided by the probability of a phone not being defective.

The probability is 0.3721 or 37.21%.
(4/25) 1/2 = 4/50 = 2/25
D. 2/25