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3 years ago

14

Can someone please help me with this?

1 answer:

Contact [7]3 years ago

4 0

Answer:

i need points

Step-by-step explanation:

i need points lol ,, hope you find your answer i guess .

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docker41 [41]

Answer: (0, 0)

<u>Step-by-step explanation:</u>

ax = by ay = 6x

$\dfrac{ax}{b}=y\qquad \quad y=\dfrac{6x}{a}$

Use substitution:

$\dfrac{ax}{b}=\dfrac{6x}{a}\\\\\\\text{Cross Multiply:}\\a^2x=6bx\\\\\\\text{Solve for x:}\\a^2x-6bx=0\\x(a^2-6b)=0\\x=\dfrac{0}{a^2-6b}\\\large\boxed{x=0}$

Substitute x = 0 to solve for y:

$\dfrac{ax}{b}=y \\\\\dfrac{a(0)}{b}=y\\\\\large\boxed{0=y}$

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3 years ago