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Rudiy27
2 years ago
15

(ASAPPPPPP!!) Just look at the bicultural and answer it PLEASEEEE

Mathematics
1 answer:
Arturiano [62]2 years ago
7 0

Answer:

<h3>(6÷6=2)663-73)773_3)</h3>
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A sequence is defined recursively using the formula f(n + 1) = –0.5 f(n) . If the first term of the sequence is 120, what is f(5
Georgia [21]

\bf \begin{array}{rrlll} term&\stackrel{f(n+1)=-0.5f(n)}{~\hfill value~ }\\ \cline{1-2} f(1)&120\\ f(2)&-0.5(120)\\ &-60\\ f(3)&-0.5(-60)\\ &30\\ f(4)&-0.5(30)\\ &-15\\ f(5)&-0.5(-15)\\ &7.5 \end{array}

4 0
3 years ago
Read 2 more answers
The population of a certain type of seahorse grew by 13% from year to year.
Gekata [30.6K]

Answer:  Exponential function

Step-by-step explanation:

A linear function is the formf(x)=mx+c , where m is the constant rate of change of y with respect to x and c is the y-intercept.

An exponential growth function is in the form f(x)=A(1+r)^x, where r is the rate of growth (generally in percent) and A is initial value.

If the population of a certain type of seahorse grew by 13% from year to year, then the rate of growth is 13% .

Hence it is an exponential equation.

7 0
3 years ago
Q15. Ken earned x dollars at his part-time job on Friday. His wife earned $12 more
Vladimir79 [104]

Answer: Ken Earned 81$

Step-by-step explanation: Subtract 12 from the total, then divide by 2 because his wife earns double than him, plus 12$ more.

Have a good day :)

3 0
1 year ago
Becky’s square living room needs new carpet. She needs about 200 square feet of carpet to cover the floor. What are the approxim
densk [106]
Area is length * width
Take the square root of 200 which is approximately 14.14
8 0
2 years ago
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Suppose a normal distribution has a mean of 222 and a standard deviation of 16. What is the probability that a data value is bet
valentina_108 [34]
Mean of the distribution = u = 222
Standard Deviation = s = 16

We have to find the probability that a value lies between 190 and 230.

First we need to convert these data values to z score.

z= \frac{x-u}{s}

For x = 190, 
z= \frac{190-222}{16}=-2

For x = 230
z= \frac{230-222}{16}=0.5

So, we have to find the percentage of values lying between z score of -2 and 0.5

P( -2 < z < 0.5) = P(0.5) - P(-2)

From standard z table, we can find and use these values.

P(-2 < x < 0.5 ) = 0.6915 - 0.0228 = 0.6687

Thus, there is 0.6887 probability that the data value will lie between 190 and 230 for the given distribution. 

5 0
3 years ago
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