Hello :
Hello:<span>
this line an equation is : y = ax+b
the slope is a : a×(4/7) = -1......( perpendicular to a line : y =4/7x-3 with a slope of 4/7)
a = -7/4 y=(-7/4)x+b
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Answer:
15x+10
Step-by-step explanation:
Answer:
The correct Option is B. Statement: ∠AFE ≅ ∠AFD Reason: Transitive Property of Equality
Step-by-step explanation:
A is true, but unnecessary. Because after proving statement A, it will imply BC ⊥ GH but that is not required.
C is also true, but this condition is also not useful in the proving the required statement which is to be proved.
D can be proved. But that is not required hence this will make the solution much bigger.
Now, let us take B. we need 2 facts to prove that lines are perpendicular when parallel lines with a transversal is given.
1. We need that the line we want to show perpendicular to the transversal and the transversal itself to form supplementary angles.
2. And the supplementary angles thus formed to be equal.
Condition 1 has been proved by the step 4.
So it must be condition 2 that you need in step 3.
∠AFD = ∠AFE
Reason : Two angles that are equal to the same angle must themselves be equal.( Transitive property of equality)
Answer:
The ratio of the circumference of a circle to the diameter of that circle is the value pi (22/7)
Step-by-step explanation:
Mathematically,
the circumference of a circle is by the formula;
C = 2 * pi * r
Now, as we know, 2r is d where r is the radius of the circle and d is the diameter of the circle
that means;
C = pi * d
hence;
C/d = pi
So the ratio of the circumference of any circle to the diameter is the value called pi