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Luba_88 [7]
3 years ago
7

there are 4 aces and 4 kings in a standard deck of 52 cards. You can pick one card at random. What is the probability of selecti

ng an ace or a king. Explain your reasoning
Mathematics
1 answer:
denis23 [38]3 years ago
3 0
There is 2/13 chance of getting an ace or king.
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HELP PLEASEEEE
Anni [7]

Given that a flyer begins from earth and thrown up with a velocity of 30 ft/sec vertically.

u = initial velocity = 30 :   a = -g = 32 ft/sec^2

s(0) =initial height  =4 ft.

We have the equation

where u = initial velocity : v= final velocity : s = distance travelled and a = acceleration.  Here final velocity is found out as follows

Substitute to get

Since v cannot be negative, the flyer’s center of gravity cannot ever reach 20 feet.

----------------------------------

To reach 25 ft, put s = 25

and v must be atleast 0

Then we have  

Hence if thrown with initial velocity of 40 ft /sec, it will reach a height of 25 ft.

7 0
3 years ago
You are petitioning the city to hold a march for a 1 mile stretch of street. The street is 45 ft wide and each sidewalk is 5 ft
Mazyrski [523]

Answer:

The approximate number of people that could fit in the 1 mile stretch is 145,200 people

Step-by-step explanation:

The length of the street = 1 mile stretch

The width of the street = 45 ft

The depth of each sidewalk = 5 ft

1 mile = 5,280 ft

Therefore;

The area of the side walk on each side of the street = 5 × 5,280 = 26,400 ft²

The area of both side walks = 26,400×2 = 52,800 ft²

The area of the street = 45 × 5,280 = 237,600 ft²

The total area of the street = The area of the street + The area of both side walks = 237,600 ft² + 52,800 ft²

The total area of the street = 290,400 ft²

The area occupied by one person is at least 2 ft²/person

Therefore, the approximate number of people that could fit in the 1 mile stretch = (The total area of the street)/(The area occupied by one person)

The approximate number of people that could fit in the 1 mile stretch = 290,400 ft²/(2 ft²/person) = 145,200 people

The approximate number of people that could fit in the 1 mile stretch = 145,200 people.

4 0
2 years ago
Hey yall what is this 345 x 345 + 687
Goshia [24]
Answer would be 119,712

345x345= 119,025

119,025 + 687 = 119,712
4 0
3 years ago
How many tens equals 1060
Cloud [144]
You will need to divide 1060 by 10 and you will get 106<span />
7 0
3 years ago
Read 2 more answers
Given the points R(-8,2) and S(-1,6), use the distance formula to find RS.
Nutka1998 [239]
1.48 hope i helped .
4 0
3 years ago
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