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3 years ago

At Kira's school, 5/9 of the 360 students bring their lunch. The other students buy lunch in the cafeteria.

Mathematics

1 answer:

sveticcg [70]3 years ago

4 0

Answer:

40 students

Step-by-step explanation:

The computation of the more students bring lunch from home rather buying them is as followS:

Given that there is 360 students out of which 5 ÷ 9 bring their lunch

= 360 × 5 ÷ 9

= 200

Now

= 360 - 200

= 160

The more students would be

= 200 - 160

= 40 students

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Caleb bought groceries and paid

lutik1710 [3]

Answer:

Price of Caleb's groceries before tax= $6.4

Step-by-step explanation:

Let price of groceries before tax be = $ $x$

Sales tax % = 2.5%

Sales tax applied = $2.5\% \ of\ x = \frac{25}{100}\times x = \frac{25}{100} x$

Actual sales tax paid = $1.60

∴ $\frac{25}{100}x=1.60$

Multiplying both sides by 100.

$100\times \frac{25}{100}x=1.60\times 100$

$25x=160$

Dividing both sides by 25.

$\frac{25x}{25}=\frac{160}{25}$

$x=6.4$

∴ Price of groceries before tax= $6.4

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4 years ago

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Mila [183]

3 and 17
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4 years ago

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Ainat [17]

Answer:

Step-by-step explanation:

4 -1 = 3

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3 years ago

Hey please help me with this one.<br><br>- Find the value fd a

valkas [14]

Answer: a = 15

Step-by-step explanation:

6a + 10 = 3a + 55

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3 years ago

the Wall Street Journal reported that automobile crashes cost United States $162 billion annually. The average cost per person f

Tanya [424]

Answer:

a) Margin of error = 166.311

b) sample size ≥ 62

Step-by-step explanation:

Given:

Average cost = $1599

Sample size = 50 persons

Standard deviation = $600

Confidence level is 95%

a) Margin of error = $z\frac{\sigma}{\sqrt{n}}$

Now for confidence level of 95% z-value = 1.96

Thus,

Margin of error = $1.96\frac{600}{\sqrt{50}}$

Margin of error = 166.311

b) For Margin of error ≤ 150

$z\frac{\sigma}{\sqrt{n}}$ ≤ 150

$1.96\frac{600}{\sqrt{n}}$ ≤ 150

$1.96\frac{600}{150}$ ≤ √n

√n ≥ 7.84

n ≥ 61.4656

Therefore,

sample size ≥ 62

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3 years ago