Answer:
15 3/4t^2 + 5 1/4
Explanation:
h(t)=-16t^2+400
We can add 400 then - 64 and show as 8^2
= h(t)=-16t^2+400 - 8^2
But we also need to change 16t^2;
We divide 64 into 16 = 16/64 =0.25
and show 16t^2 changes by 0.25 = 1/4
15 3/4t^2 + 400-64
Can now look like
15 3/4t^2 + 5 1/4
As 5 1/4 = 64 x 5 1/4 = 336
Definately option C
- As it's mentioned y=x+4 it must be function
- So in function every domain has its unique range.
- Hence here the slope is not constant
As
The graph shown is a parabola which is not y=x+4
So option C is wrong
Let P(a, b) be a point on the coordinate plane. Then the following hold:
i) If a>0, b>0 then P is in the I.Quadrant.
ii) If a<0, b>0 then P is in the II.Quadrant.
iii) If a<0, b<0 then P is in the III.Quadrant.
iv) If a>0, b<0 then P is in the IV.Quadrant.
v) If a=0 and b is positive or negative, then P is on the y-axis.
vi) If b=0 and a is positive or negative, then P is on the x-axis.
Since we have: a=0, and 19 positive, then this point is on the y-axis.
Answer: y-axis
Step-by-step explanation:
<u>Given equation:</u>
a. write a second equation so that (1,3) is the only solution of the system
To have only one solution the equation must have a different slope.
<u>Let it be 10, then the y-intercept of y = 10x + b is:</u>
<u>And the equation:</u>
b. Write a second equation so that the system has infinitely many solutions
<u>To have infinitely many solutions, both equations must be same:</u>
c. Write a second equation so that the system has no solutions.
<u>To have no solutions, the equations must have same slope but different y-intercepts:</u>
Answer:
For the first city, the 95% confidence interval would be:
28,900 +/- 2300 x 3 = 28,900 +/-6900$
For the second city, the 95% confidence interval would be:
30,300 +/- 2100 x 3 = 30,300 +/- 6300$
