F(x) = 16ˣ

A. g(x) = 8(2ˣ)
g(x) = (2³)(2ˣ)
g(x) = 2ˣ⁺³
The answer is not A.

B. g(x) = 4096(16ˣ⁻³)
g(x) = (16³)(16ˣ⁻³)
g(x) = 16ˣ
The answer is B.

C. g(x) = 4(4ˣ)
g(x) = 4ˣ⁺¹
The answer is not C.

D. g(x) = 0.0625(16ˣ⁺¹)
g(x) = (16⁻¹)(16ˣ⁺¹)
g(x) = 16ˣ
The answer is D.

E. g(x) = 32(16ˣ⁻²)
g(x) = (2⁵)(2⁴ˣ⁻⁸)
g(x) = 2(⁴ˣ⁻³)
The answer is not E.

F. g(x) = 2(8ˣ)
g(x) = 2(2³ˣ)
g(x) = 2³ˣ⁺¹
The answer is not F.

The answer is B and D.

6 0

3 years ago

Suppose the mean SAT verbal score is 525 with a standard deviation of 100, while the mean SAT math score is 575 with a standard

Ipatiy [6.2K]

Answer:

The mean of the combined math and verbal scores is 1100, while the standard deviation is 141.

Step-by-step explanation:

Normal variables

Normal variables have mean $\mu$ and standard deviation $\sigma$

When we add normal variables, the combined mean is the sum of both means, and the standard deviation is the square root of the sum of both variances. The distribution is still normal.

In this question:

Verbal: $\mu_{V} = 525, \sigma_{V} = 100$ .

Math: $\mu_{M} = 575, \sigma_{M} = 100$

Combined:

$\mu = \mu_{V} + \mu_{M} = 525 + 575 = 1100$

$\sigma = \sqrt{\sigma_{V}^{2}+\sigma_{M}^{2}} = \sqrt{100^2 + 100^2} = 141$

The mean of the combined math and verbal scores is 1100, while the standard deviation is 141.

6 0

3 years ago