A. 3, $160 because
Y = 50x + 10
Y = 30x + 70
Step 1 substitute your first number (3) for X .
Step 2 Solve . 50(3) = 150 + 10 = 160
30(3) = 90 + 70 = 160 Which Is Your Answer
9514 1404 393
Answer:
2. 15 cents/min
3. 7/4 gallon/week = 1.75 gal/wk
Step-by-step explanation:
You want to convert the units without changing the rate. You do this by making use of conversion factors. Each conversion factor has a value of 1, but changes the units. (It has a value of 1 because the quantity in the numerator is equal to the quantity in the denominator.)
In general, you know that when the numerator and denominator of a fraction are the same thing, they cancel, leaving a value of 1. When a variable (or unit) is involved, the cancelled variables (or units) simply disappear.
For example, multiplying (9 dollars)×(100 cents)/(1 dollar) gives ...

The units of "dollar" cancel, leaving cents. Note that we did this by choosing a conversion factor with units we want in the place we want, and units we don't want on the other side of the fraction bar.
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2) We want cents in the numerator, so our conversion factor will be (100 cents)/(1 dollar). And we want minutes in the denominator, so our other conversion factor will be (1 hour)/(60 minutes). Multiplying by these conversion factors, our rate becomes ...

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3) We want gallons in the numerator, so that conversion will be done by (1 gal)/(8 pt). We want weeks in the denominator, so the conversion for that is (7 day)/(1 week).

54-30/3=54-10=44
The blanks are 30, 10 and 44
Answer:

Step-by-step explanation:
According to Angles of intersecting chords theorem:
∠GAJ = 
Where ∠GAJ = 50 , BD = 24 and GJ = ?
50 = 
Multiplying both sides by 2
100 = 24 + GJ
GJ = 100-24
GJ = 76 degrees
Answer:
Step-by-step explanation:
<em>The probability that a point chosen at random in the given figure will be inside the larger square and outside the smaller square</em> is equal to the ratio of the area of interest to the total area:
<em>P(inside larger square and outside smaller square)</em> = area of interest / total area
<em>P(inside larger square and outside smaller square)</em> = area inside the larger square and outside the smaller square / area of the larger square
<u>Calculations:</u>
<u />
1. <u>Area inside the larger square</u>: side² = (10 cm)² = 100 cm²
2. <u>Area inside the smaller square </u>= side² = (7cm)² = 49 cm²
3. <u>Area inside the larger square and outside the smaller square</u>
- 100 cm² - 49 cm² = 51 cm²
4.<u> P (inside larger square and outside smaller squere)</u>
- 51 cm² / 100 cm² = 51/100