Answer:
100
Step-by-step explanation:
We have the sum of first n terms of an AP,
Sn = n/2 [2a+(n−1)d]
Given,
36= 6/2 [2a+(6−1)d]
12=2a+5d ---------(1)
256= 16/2 [2a+(16−1)d]
32=2a+15d ---------(2)
Subtracting, (1) from (2)
32−12=2a+15d−(2a+5d)
20=10d ⟹d=2
Substituting for d in (1),
12=2a+5(2)=2(a+5)
6=a+5 ⟹a=1
∴ The sum of first 10 terms of an AP,
S10 = 10/2 [2(1)+(10−1)2]
S10 =5[2+18]
S10 =100
This is the sum of the first 10 terms.
Hope it will help.
Answer:
ΔABD ≅ ΔACD by SAS, therefore;
by CPCTC
Step-by-step explanation:
The two column proof is presented as follows;
Statement 
Reason
ABCD is a trapezoid Given
Given
Definition of a trapezoid
ABCD is an isosceles trapezoid Left and right leg are equal
∠BAD ≅ ∠CDA Base angle of an isosceles trapezoid are congruent
Reflexive property
ΔABD ≅ ΔACD By SAS rule of congruency
CPCTC
CPCTC; Congruent Parts of Congruent Triangles are Congruent
SAS; Side Angle Side rule of congruency
Answer:
88unit^2
Step-by-step explanation:Area=
1/2(17+27)*4
Area=88unit^2
You can make four batches of cookies with four eggs left over. 5 goes into 24 four times with a remainder of 4.
