3 years ago

Negative one half minus negative five ninths

Mathematics

1 answer:

Ymorist [56]3 years ago

6 0

Answer: -101/18

Step-by-step explanation: I think, I don’t know

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Graph answer:
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N is the answer to this question

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LekaFEV [45]

Answer:

$(a)\ \sqrt{20}=2\sqrt{5}$

$(b)\ \sqrt{300} = 10 \sqrt{3}$

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Step-by-step explanation:

Required

Simplify

$(a)\ \sqrt{20}$

Express 20 as 4 * 5

$\sqrt{20}=\sqrt{4 * 5}$

Split

$\sqrt{20}=\sqrt{4} * \sqrt{5}$

This gives:

$\sqrt{20}=2 * \sqrt{5}$

$\sqrt{20}=2\sqrt{5}$

$(b)\ \sqrt{300$

Express as 100 * 3

$\sqrt{300} = \sqrt{100} * \sqrt{3}$

This gives:

$\sqrt{300} = 10 * \sqrt{3}$

$\sqrt{300} = 10 \sqrt{3}$

$(c)\ \sqrt{128}$

Express as 64 * 2

$\sqrt{128} = \sqrt{64*2}$

Split

$\sqrt{128} = \sqrt{64} * \sqrt{2}$

$\sqrt{128} = 8 * \sqrt{2}$

$\sqrt{128} = 8 \sqrt{2}$

Questions 4 and 5 are not clear

Follow the steps in 1 - 3 to solve 4 and 5

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Answer:

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Step-by-step explanation:

The graphs starts from X=1 and remains defined from X =1 to infinity. The domain of the function is, thus, [-1, infinity)

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