The following lines: y=2/3(x) and y=-3/2(x) are...

Helppppppppppppppppppppp

poizon [28]

Answer:

A

Step-by-step explanation:

Look at both rectangles and list each of the corners coordinates:

The rectangle on the left has coordinates:

R: (-4,-1)

S: (-1,-1)

T: (-1,-3)

U: (-4,-3)

Now because the rectangle transformed to a different location we should take the coordinates of each of its vertices to find what type of transformation this is:

R' : (4,-1)

S' : (1,-1)

T' : (1,-3)

U' : (4,-3)

We can notice that the difference between both sets of points is that the x-value changes sign and the y-values stay the same, therefore the answer is A

5 0

3 years ago

There are 660 counters in a bag 1/6 of the counters are red 25% are blue and the rest are green how many green counters are ther

allsm [11]

Answer:

385 counters

Step-by-step explanation:

Since 1/6 of the counters are red and 1/4 of the counters are blue, there are:

1 - (1 / 6) - (1 / 4) = 7 / 12

Multiply it to find green:

660 x (7 / 12) = 385 counters

6 0

3 years ago

The distance from c to d?

myrzilka [38]

Pretty sure it’s
A. 7 units.

4 0

3 years ago

Find the general solution, y(t), which solves the problem below, by the method of integrating factors.

Sonbull [250]

The general solution, y(t), which solves the problem by the method of integrating factors is; y = ¹/₂₁t⁴ + (1/t)c₁t^(⁴/₅)

<h3>How to solve differential equations?</h3>

We want to find the general solution of;

5t(dy/dt) + y = t⁴

We will divide through by 5t to get;

(dy/dt) + y/5t = t³/6

Using Integration factor, we have;

u(t) = e^∫(¹/₅t) dt = t^(¹/₅)

Thus, we now have;

[t^(¹/₅)](dy/dt) + [t^(¹/₅)]y/5t = [t^(¹/₅)]t³/6

Completing this with a differential calculator gives us the general solution as;

y = ¹/₂₁t⁴ + (1/t)c₁t^(⁴/₅)

Read more about differential equations at; brainly.com/question/17201048

#SPJ1

7 0

3 years ago

A professor knows that her statistics students' final exam scores have a mean of 79 and a standard deviation of 11.3. In his cla

OverLord2011 [107]

For each student, there are only two possible outcomes. Either they score an A, or they do not. The probability of a student scoring an A is independent of any other student, which means that the binomial probability distribution is used to solve this question.

Additionally, to find the proportion of students who scored an A, the normal distribution is used.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean and standard deviation , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Proportion of students that scored an A:

Scores have a mean of 79 and a standard deviation of 11.3, which means that $\mu = 79, \sigma = 11.3$

Scores of 90 or higher are graded an A, which means that the proportion is 1 subtracted by the p-value of Z when X = 90, so:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{90 - 79}{11.3}$

$Z = 0.97$

$Z = 0.97$ has a p-value of 0.8340.

1 - 0.8340 = 0.166

The proportion of students that scored an A is 0.166.

Probability that 6 students or more will score an "A" on the final exam:

Binomial distribution.

22 students, which means that $n = 22$

The proportion of students that scored an A is 0.166, which means that $p = 0.166$

The probability is:

$P(X \geq 6) = 1 - P(X < 6)$

In which

$P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)$

Then

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{22,0}.(0.166)^{0}.(0.834)^{22} = 0.0184$

$P(X = 1) = C_{22,1}.(0.166)^{1}.(0.834)^{21} = 0.0807$

$P(X = 2) = C_{22,2}.(0.166)^{2}.(0.834)^{20} = 0.1687$

$P(X = 3) = C_{22,3}.(0.166)^{3}.(0.834)^{19} = 0.2239$

$P(X = 4) = C_{22,4}.(0.166)^{4}.(0.834)^{18} = 0.2117$

$P(X = 5) = C_{22,5}.(0.166)^{5}.(0.834)^{17} = 0.1517$

Then

$P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.0184 + 0.0807 + 0.1687 + 0.2239 + 0.2117 + 0.1517 = 0.8551$

$P(X \geq 6) = 1 - P(X < 6) = 1 - 0.8551 = 0.1449$

Thus

0.1449 = 14.49% probability that 6 students or more will score an "A" on the final exam.

For a problem that used the normal distribution, you can check brainly.com/question/15181104, and for a problem that used the binomial distribution, you can check brainly.com/question/15557838

3 0

3 years ago