Quadrilateral ABCD with AB = 5.5cm, BC = 3.5cm, CD = 4cm, AD = 5cm, and <A = 45°.
2 answers:
Answer:
- Draw a line segment AB = 5.5 cm » Take A as a center and draw an
angle of 45°
- Cut off AD = 5 cm
- Take D as a center with radius
4.5 cm and draw an arc.
- Take B as a center with radius 3.5 cm and draw an arc, which
meets previous arc at point c.
- Join BC and CD.
therefore ABCD is a required quadrilateral.
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Tree casts a shadow 30 feet long. A MHS student standing near the tree casts a shadow 9 feet long. The student is 6 feet tall. What is the height of the tree? Show all work
<em><u>Answer:</u></em>
Option D
The height of tree is 20 feet tall
<em><u>Solution:</u></em>
From given question,
Shadow of tree = 30 feet
Height of tree = ?
Height of student = 6 feet
Shadow of student = 9 feet
We have to find the height of tree
We can solve the sum by proportion
This forms a proportion and we can solve the sum by cross multiplying
Thus height of tree is 20 feet tall