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Olin [163]
3 years ago
14

Kristy had a piece of fabric that she cut into 8 equal squares. Each square has area 0.625 ft2. What is the area of Kristy's ori

ginal piece of fabric?
ft2


PLS HELPPP
Mathematics
1 answer:
kkurt [141]3 years ago
7 0

Answer:

5ft^2 is the area of the original piece of fabric.

Step-by-step explanation:

0.625 x 8 = 5

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b

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A room is 18ft long by 18ft wide. A blueprint shows the room to be 3.5 inches long. What is the width of the room in the bluepri
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You have been doing research for your statistics class on the prevalence of severe binge drinking among teens. You have decided
Serggg [28]

Answer:

(1.218 ; 1.322)

the confidence interval is appropriate

Step-by-step explanation:

The confidence interval :

Mean ± margin of error

Sample mean = 1.27

Sample standard deviation, s = 0.80

Sample size, n = 914

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Margin of Error = Tcritical * s/√n

Tcritical at 95% ; df = 914 - 1 = 913

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Mean ± margin of error

1.27 ± 0.05186

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(1.218 ; 1.322)

According to the central limit theorem, sample means will approach a normal distribution as the sample size increases. Hence, the confidence interval is valid, the sample size of 914 gave a critical value at 0.05 which is only marginally different from that will obtained using a normal distribution table. Hence, the confidence interval is appropriate

8 0
3 years ago
Answer correct you get brainliest answer​
zloy xaker [14]

Answer:

y =  {x}^{2}  - 2

Or if you want with the value of h too.

y =  {(x - 0)}^{2}  - 2

Step-by-step explanation:

y = a {(x - h)}^{2}  + k

Find the value of h and k by using the formula.

h =  -  \frac{b}{2a}  \\ k =  \frac{4ac -  {b}^{2} }{4a}

From y = x²-2

a = 1 \\ b = 0 \\ c =  - 2

Substitute these values in the formula.

h =  -  \frac{0}{2(1)}  \\ h = 0

Therefore, h = 0.

k =  \frac{4(1)( - 2) -  {0}^{2} }{4(1)}  \\ k =  \frac{ - 8}{4}  \\ k =  - 2

Therefore, k = - 2.

From the vertex form, the vertex is at (h, k) = (0,-2). Substitute h = 0, a = 1 and k = -2 in the equation.

y = a {(x - h)}^{2}  + k \\ y = 1 {(x - 0)}^{2}  - 2 \\ y =  {(x)}^{2}  - 2 \\ y =  {x}^{2}  - 2

These type of equation where b = 0 can also be both standard and vertex form.

4 0
3 years ago
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