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3 years ago

Friends help me outstate true or false0 is the multiplicative inverse of 0?

Mathematics

1 answer:

vazorg [7]3 years ago

6 0

Answer:

false

Step-by-step explanation:

I say false because the multiplicative inverse of 0 is undefined and the multiplicative inverse tells us that when you multiply a number by its inverse the product will be1 think the multiplicative inverse of 0 is undefined.

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3 years ago

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3 years ago

A bookstore had 45 copies of a magazine. Yesterday, it sold 13 of them. Today, it sold 23 of what remained. How many copies does

Elan Coil [88]

Answer:

Step-by-step explanation:

Total initially in bookstore = 45

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2 years ago

A machine that produces ball bearings has initially been set so that the true average diameter of the bearings it produces is .5

Elodia [21]

Answer:

7.3% percentage of the bearings produced will not be acceptable.

Step-by-step explanation:

Consider the provided information.

Average diameter of the bearings it produces is .500 inches. A bearing is acceptable if its diameter is within .004 inches of this target value.

Let X is the normal random variable which represents the diameter of bearing.

Thus, 0.500-0.004<X<0.500+0.004

0.496<X<0.504

The bearings have normally distributed diameters with mean value .499 inches and standard deviation .002 inches.

Use the Z score formula: $\frac{X-\mu}{\sigma}$

Therefore

$\frac{0.496-0.499}{0.002}\leq z\leq \frac{0.504-0.499}{0.002}$

$\frac{-0.003}{0.002}\leq z\leq \frac{0.005}{0.002}$

$-1.5\leq z\leq 2.5$

Now use the standard normal table and determine the probability of that a ball bearing will be acceptable.

$P(-1.5\leq z\leq 2.5)=0.9938-0.0668=0.9270$

We need to find the percentage of the bearings produced will not be acceptable.

So subtract it from 1 as shown.

1-0.9270=0.073

Hence, 7.3% percentage of the bearings produced will not be acceptable.

3 0

3 years ago

Friends help me outstate true or false0 is the multiplicative inverse of 0?​

Friends help me outstate true or false0 is the multiplicative inverse of 0?