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Annette [7]
3 years ago
13

The mathletes needed $932.50 to attend a competition in Boston .the bus cost $550 and meals for the tournament costs $22.50 for

each student. How many students were able to attend the tournament.?
Mathematics
1 answer:
Strike441 [17]3 years ago
4 0
Answer:1
Step by step equation
Add the cost of the trip together then subtract from total cost needed to attend you would only have $360 dollars left which isn’t enough to take another students so the answer is 1
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ILL MARK BRAINIEST IF YOU CAN DO THIS RIGHT!!!
Bumek [7]

Answer:  Slope: -1/2  

Step-by-step explanation:  To find slope take 2 points that lie on the line and use this formula to solve:  <em> </em>I will use (0, -2) and (2, -3) to solve

                                                                       ↑    ↑           ↑   ↑

y2 - y1                                                             x1  y1          x2  y2

-----------

x2 - x1

So, for this question, substitute the x and y values from the points above to solve.

-3 - (-2)      

----------- =  - 1/2

2 - 0

Hope this helped. :)

 

5 0
2 years ago
What is the answer to this question
DanielleElmas [232]

Answer:

65

Step-by-step explanation:

the angle on top is the same  because the lengths of the lines that meet to "H" are the same.

7 0
2 years ago
What is the sum of all positive integers less than 300 which are divisible by 3
drek231 [11]

Answer:

14,850

Step-by-step explanation:

You need the sum of

3 + 6 + 9 + 12 + ... + 294 + 297

Factor out a 3 from the sum

3 + 6 + 9 + 12 + ... + 294 + 297 = 3(1 + 2 + 3 + 4 + ... + 98 + 99)

You need to add all integers from 1 to 99 and multiply by 3.

The sum of all consecutive integers from 1 to n is:

[n(n + 1)]/2

The sum of all consecutive integers from 1 to 99 is

[99(99 + 1)]/2

The sum you need is 3 * [99(99 + 1)]/2

3 + 6 + 9 + 12 + ... + 294 + 297 =

= 3 * [99(99 + 1)]/2

= 3 * [99(100)]/2

= 3 * 9900/2

= 14,850

4 0
2 years ago
I need help please help me
iogann1982 [59]

<u>M</u><u>e</u><u>t</u><u>h</u><u>o</u><u>d</u><u> </u><u>1</u><u> </u><u>:</u>

replace x and y by their value 1 and 3

3 = 4(1) - 1 = 4-1 = 3

2(1) + 3 = 2 + 3 = 5

correct

<u>M</u><u>e</u><u>t</u><u>h</u><u>o</u><u>d</u><u> </u><u>2</u><u> </u><u>:</u>

y = 4x - 1

2x + y = 5

y = 4x - 1

y = -2x + 5

y - y = 4x - 1 - ( -2x + 5 )

0 = 4x - 1 + 2x - 5

6x - 6 = 0

6x = 6

x = 6/6 = 1

y = 4x - 1

y = 4(1) - 1

y = 3

correct

4 0
2 years ago
Read 2 more answers
In 2000 the total amount of gamma ray bursts was recorded at 6.4 million for a city. In 2005, the same survey was made and the t
ratelena [41]

Let's assume

It started in 2000

so, t=0 in 2000

P_0=6.4million

we can use formula

P(t)=P_0 e^{rt}

we can plug value

P(t)=6.4 e^{rt}

In 2005, the same survey was made and the total amount of gamma ray bursts was 7.3 million

so, at t=2005-2000=5

P(t)=7.3 million

we can plug value and then we can solve for r

7.3=6.4 e^{r*5}

r=0.02632

now, we can plug back

P(t)=6.4 e^{0.02632t}

now, we have

P(t)=1 billion =1000 million

so, we can set it and then we can solve for t

1000=6.4 e^{0.02632t}

t=191.924

approximately

t=192

Year is 2000+192

year is 2192................Answer

4 0
3 years ago
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