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Arisa [49]
3 years ago
10

Which of these numbers are perfect squares or perfect cubes? Select the THREE answers that apply. 8 16 32/ 64 128 6 Omestian 12​

Mathematics
1 answer:
Murljashka [212]3 years ago
8 0

Answer:

  8, 16, 64

Step-by-step explanation:

  8 = 2^3 . . . a perfect cube

  16 = 4^2 . . . a perfect square

  32 = 2^5 . . . neither a cube nor a square

  64 = 2^6 = 4^3 = 8^2 . . . both a perfect cube and a perfect square

  128 = 2^7 . . . neither a cube nor a square

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I need to find the derivative. I’m not very good at this so I am answer asap would be sosososo helpful
Bingel [31]

Answer:

See below.

Step-by-step explanation:

First, notice that this is a composition of functions. For instance, let's let f(x)=\sqrt{x} and g(x)=7x^2+4x+1. Then, the given equation is essentially f(g(x))=\sqrt{7x^2+4x+1}. Thus, we can use the chain rule.

Recall the chain rule: \frac{d}{dx}[f(g(x))]=f'(g(x))\cdot g'(x). So, let's find the derivative of each function:

f(x)=\sqrt{x}=x^\frac{1}{2}

We can use the Power Rule here:

f'(x)=(x^\frac{1}{2})'=\frac{1}{2}(x^{-\frac{1}{2}  })=\frac{1}{2\sqrt{x}}

Now:

g(x)=7x^2+4x+1

Again, use the Power Rule and Sum Rule

g'(x)=(7x^2+4x+1)'=(7x^2)'+(4x)'+(1)'=14x+4

Now, we can put them together:

y'=f'(g(x))\cdot g'(x)=\frac{1}{2\sqrt{g(x)}} \cdot (14x+4)

y'=\frac{14x+4}{2\sqrt{7x^2+4x+1} } =\frac{7x+2}{\sqrt{7x^2+4x+1} }

5 0
3 years ago
Consider a game in which a participant pays $2 to roll a die. The participant receives $3 if they roll a 1 (i.E. They go up by a
Sauron [17]

Answer:

The expected monetary value of a single roll is $1.17.

Step-by-step explanation:

The sample space of rolling a die is:

S = {1, 2, 3, 4, 5 and 6}

The probability of rolling any of the six numbers is same, i.e.

P (1) = P (2) = P (3) = P (4) = P (5) = P (6) = \frac{1}{6}

The expected pay for rolling the numbers are as follows:

E (X = 1) = $3

E (X = 2) = $0

E (X = 3) = $0

E (X = 4) = $0

E (X = 5) = $0

E (X = 6) = $4

The expected value of an experiment is:

E(X)=\sum x\cdot P(X=x)

Compute the expected monetary value of a single roll as follows:

E(X)=\sum x\cdot P(X=x)\\=[E(X=1)\times \frac{1}{6}]+[E(X=2)\times \frac{1}{6}]+[E(X=3)\times \frac{1}{6}]\\+[E(X=4)\times \frac{1}{6}]+[E(X=5)\times \frac{1}{6}]+[E(X=6)\times \frac{1}{6}]\\=[3\times \frac{1}{6}]+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]\\+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]+[4\times \frac{1}{6}]\\=1.17

Thus, the expected monetary value of a single roll is $1.17.

7 0
3 years ago
A person has a mass of 70 kg. Express this mass in g.​
yulyashka [42]
70000 grams in total
7 0
3 years ago
This polygon is a Quadrilateral (4 sided
Leto [7]

Answer:

Step-by-step explanation:

3x° + 60° = 360°

3x = 360 - 60

3x = 300

x° = 100°

7 0
3 years ago
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brilliants [131]

Answer:

C. 37x + 35

Step-by-step explanation:

8(5x  + 1) + 3(9 - x) \\  \\40x + 8 + 27 - 3x \\ 40x - 3x + 27 + 8 \\ 37x + 35

5 0
2 years ago
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