Easy peasy
slope=(change in rise)/(change in run)
aka
slope between points (x1,y1) and (x2,y2) is
slope=(y2-y1)/(x2-x1) since y is rise/up and x is run/leftright
points
(-7,-9) and (-5,-8)
x1=-7
y1=-9
x2=-5
y2=-8
remember minusing a negative means addin a positive
slope=(-8-(-9))/(-5-(-7))=
(-8+9)/(-5+7)=1/2
slope=1/2
positive slopes go from bottom left to top right
since it is less than 1
it is more horizonal than vertical
Since the co-efficient or "r" is "-3" and "-3", it will simplify to "-6" as -3-3= -6.
then the two constant terms with are "7" and "-12" will simplify to "-5" as 7-12=-5. therefore, the simplest form is -6r -5
hope it helped!
Answer:
Step-by-step explanation:
Given that,
y' = 17y ( 1-y^7)
Let y=1
Then, y' = 0 for all t
Then show that it is the only stable equilibrium point so that as y→1, t→∞ with any initial value.
So, the graph solution will be
y(0) = 1 and this will be an horizontal line
If, y(0) > 1 then, y' < 0 by inspecting the first equation, so the graph is has decreasing solution.
Likewise, if y(0) < 1 then, y' > 0 and the graph is increasing.
So no matter the initial condition, graph of the solution will be asymptotic to the horizontal line above.
This make the limit be 1.
This shows that x = 1 is a stable equilibrium.
Answer
- 3/2
Step-by-step explanation:
Hope this helps:) if you need anynore help lmk!
