All categories

2 years ago

Which is greater: 10cm or 103mm? How much greater?

Mathematics

1 answer:

bekas [8.4K]2 years ago

6 0

Answer:

0.3cm and/or 3mm

Step-by-step explanation:

When converting 10cm to mm you get 100mm and when putting 100mm to 103mm its visible that the 103mm is larger, but by how much? The difference is 0.3cm and/or 3mm.

You might be interested in

Two angles are supplementary. The first angle has 20 degreesmore the second angle. How ma y degrees are in each angle?

Vanyuwa [196]

Answer:

100 and 80

Step-by-step explanation:

Let x = be the first angle

x-20 is the second angle

They are supplementary so they add to 180

x+x-20 = 180

Combine like terms

2x-20 =180

2x-20+20 =180+20

2x= 200

Divide by 2

2x/2 = 200/2

x= 100

The first angle is 100 and the second is x-20

x-20 = 100-20=80

The two angles are 100 and 80

3 0

2 years ago

A college student needs 15 classes that are worth a total of 40 credits in order to complete her degree. The college offers both

mars1129 [50]

12 three credit classes and two 2 credit classes

EXPLINATION:

12x3=36
2x2=4

And when you add you’re products together you get you get 40

6 0

2 years ago

Evaluate AB for A = 5, B =-2, C = 4 and D = -6.<br> 5/12<br> -5/12<br> -3/2<br> 3/2

Nezavi [6.7K]

Answer:

AB = -10

Im confused is this what you wanted?

5 0

2 years ago

A road perpendicular to a highway leads to a farmhouse located d miles away. An automobile traveling on this highway passes thro

pshichka [43]

Answer:

$\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+900}}$

Step-by-step explanation:

A road is perpendicular to a highway leading to a farmhouse d miles away.

An automobile passes through the point of intersection with a constant speed $\frac{dx}{dt}$ = r mph

Let x be the distance of automobile from the point of intersection and distance between the automobile and farmhouse is 'h' miles.

Then by Pythagoras theorem,

h² = d² + x²

By taking derivative on both the sides of the equation,

$(2h)\frac{dh}{dt}=(2x)\frac{dx}{dt}$

$(h)\frac{dh}{dt}=(x)\frac{dx}{dt}$

$(h)\frac{dh}{dt}=rx$

$\frac{dh}{dt}=\frac{rx}{h}$

When automobile is 30 miles past the intersection,

For x = 30

$\frac{dh}{dt}=\frac{30r}{h}$

Since $h=\sqrt{d^{2}+(30)^{2}}$

Therefore,

$\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+(30)^{2}}}$

$\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+900}}$

3 0

3 years ago

Confused!! consider the polar axes with the points plotted below. Write the coordinates of point A in polar form. Be sure to wri

irinina [24]

Point A is on the 4th circle from the center, each circle has a radius of 1, so the 4th circle has a radius of 4. The point is also on the angle labeled 5PI/6.

The polar coordinate would be (4, 5PI/6)

Point C, you are given (-3,pi/3)

Because the radius is positive find the 3rd circle, which would be r = 3, Then find where PI/3 is on the circle and find the value opposite that which is 4pi/3

7 0

3 years ago