Answer:
The correct answer is - 26 sums for pulling few coins.
Step-by-step explanation:
Given:
coins in the wallet = 5 ($0.05, $0.10, $0.25, $1.00 and $2.00)
Different sums of money = ?
Formula: Different combination of items can be calculated with the help of a formula of combination that is -
nCr = n! / ((n – r)! r!)
where, n = total number of items
r = number of item in a set
solution:
In this question number of set is not given only few mention so the sets could be 2 coins, 3 coins, 4 coins and 5 coins.
a. for set of 2 coins
= 5! / ((5 – 2)! 2!)
= 20/2
= 10 combination of sums
b. for the set of 3 coins
= 5! / ((5 – 3)! 3!)
= 10
C. for 4
= 5! / ((5 – 4)! !)
= 5
d. for 5 coins
only 1 sum
thus, the total types of different sums = 10+10+5+1
= 26.
