Question

CuO+H₂ → Cu +H₂O redox equation

Answer 1

Answer:

Cu   H₂O

Explanation:

CuO + H₂  -----> Cu + H₂O

Oxidation : Gaining of oxygen OR Losing of hydrogen

Reduction : Gaining of Hydrogen OR Losing of Oxygen

Here ,

CuO gets reduced [ it loses oxygen ] and become Cu

H₂ gets oxidized  [ it gains oxygen ] and becomes H₂O

Substance that gets oxidised = H₂

Substance that gets reduced = CuO

Also ,

Oxidising agent = substance that gets reduced = CuO

Reducing agent = substance that gets oxidized = H₂

Answer 2

Answer:

Cu⁺² + 2e⁻ → Cu

Explanation:

A redox reaction is the half-equation where the element is reduced (gains electrons).

Compounds always have to have oxidation numbers that add to 0.

Oxygen's oxidation number is -2.

Stand alone elements always have an oxidation number of 0.

Reactants

Because Copper's oxidation number + Oxygen's oxidation number = 0, and Oxygen's oxidation number = -2, we know Copper's oxidation number is +2.

H₂ has to have a net oxidation of 0, so Hydrogen's oxidation number is 0.

Products

Copper's oxidation number is 0 because it's a standalone element.

2 * Hydrogen's oxidation number + Oxygen's oxidation number = 0, so that means Oxygen's oxidation number is -2, and Hydrogen's is +1.

Because Copper's oxidation number went down from +2 to 0, that means it gained electrons and therefore was reduced. So your answer is:

Cu⁺² + 2e⁻ → Cu