Answer:
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Answer:
An Orbital is best described as the volume of space in which electrons are most often found
Explanation:
As we know atom consists of sub-particles commonly known as protons, neutrons and electrons. The outer space around the nucleus where the probability of finding electrons is maximum is known as orbital. As the electrons are not precisely ordered around the nucleus hence it is not easy to tell the exact position of an electron.
Hence, four quantum numbers are used to locate the position of electrons around the nucleus.
i) Principle Quantum Number:
This number explains the main energy level which tend to increase in energy as the distance of electrons from nucleus are increased. Principle Quantum Numbers are integer number ranging from one to infinity. Hence, increase in this quantum number results in increase of the size of orbital.
ii) Azimuthal Quantum Number:
This Quantum Number explains the direction of particular orbital in 3-dimensional space. Also it is responsible for the shape of an orbital.
iii) Magnetic Quantum Number:
This Quantum Number also tells the direction of orbital in 3D space with respect to x, y and z axis.
iv) Spin Quantum Number:
This Quantum Number tells about the spin direction of an electron about its axis which may be clockwise or anticlockwise.
Formic acid is the simplest carboxylic acid with a structure of HCOOH and has a pka of 3.75. The pka refers to the acidity of the molecule, which in this example refers to the molecules ability to give up the proton of the O-H. A decrease in the pka value corresponds to an increase in acidity, or an increase in the ability to give up a proton. When an acid gives up a proton, the remaining anionic species (in this case HCOO-) is called the conjugate base, and an increase in the stability of the conjugate base corresponds to an increase in acidity.
The pka of a carboxylic can be affected greatly by the presence of various functional groups within its structure. An example of an inductive effect changing the pka can be shown with trichloroacetic acid, Cl3CCOOH. This molecule has a pka of 0.7. The decrease in pka relative to formic acid is due to the presence of the Cl3C- group, and more specifically the presence of the chlorine atoms. The electronegative chlorine atoms are able to withdraw the electron density away from the oxygen atoms and towards themselves, thus helping to stabilize the negative charge and stabilize the conjugate base. This results in an increase in acidity and decrease in pka.
The same Cl3CCOOH example can be used to explain how dipoles can effect the acidity of carboxylic acids. Compared to standard acetic acid, H3CCOOH with a pka of 4.76, trichloroacetic acid is much more acidic. The difference between these structures is the presence of C-Cl bonds in place of C-H bonds. A C-Cl bond is much more polar than a C-H bond, due the large electronegativity of the chlorine atom. This results in a carbon with a partial positive charge and a chlorine with a partial negative charge. In the conjugate base of the acid, where the molecule has a negative charge localized on the oxygen atoms, the dipole moment of the C-Cl bond is oriented such that the partial positive charge is on the carbon that is adjacent to the oxygen atoms containing the negative charge. Therefore, the electrostatic attraction between the positive end of the C-Cl dipole and the negative charge of the anionic oxygen helps to stabilize the entire species. This level of stabilization is not present in acetic acid where there are C-H bonds instead of C-Cl bonds since the C-H bonds do not have a large dipole moment.
To understand how resonance can affect the pka of a species, we can simply compare the pka of a simple alcohol such as methanol, CH3OH, and formic acid, HCOOH. The pka of methanol is 16, suggesting that is is a very weak acid. Once methanol gives up that proton to become the conjugate base CH3O-, the charge cannot be stabilized in any way and is simply localized on the oxygen atom. However, with a carboxylic acid, the conjugate base, HCOO-, can stabilize the negative charge. The lone pair electrons containing the charge on the oxygen atom are able to migrate to the other oxygen atom of the carboxylic acid. The negative charge can now be shared between the two electronegative oxygen atoms, thus stabilizing the charge and decreasing the pka.
Answer:
FADH2 is a reducing agent.
FAD is an oxidizing agent.
Explanation:
The full form of FAD is flavin adenine dinucleotide. It is mainly a redox-active coenzyme which is associated with the different proteins and is involved with the enzymatic reactions in the metabolism.
FAD is obtained by donating or accepting electrons.
In the citric acid cycle,
succinate + FAD → fumarate + 
Thus we see that FAD is an oxidizing agent while is a reducing agent.
Explanation:
solution 1) homogeneous
2) do not scatter light
3) cannot be separated by filtration
Colloids 1) heterogeneous
2) scatter light
3) cannot be separated by filtration
suspension 1) heterogeneous
2) may either scatter light or be opaque
3) can be separated by filtration
