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BigorU [14]
2 years ago
7

Write the electronic configuration for 40/20 Ca

Chemistry
1 answer:
KiRa [710]2 years ago
3 0

Answer:

[AR] 4s². EC(Ca)=1s² 2s² 2p⁶ 3s² 3p⁶ 4s²

S=shell

²or⁶ is number of electrons

Explanation:

the number of electrons for the calcium atom is 20 show the first two electrons of calcium will go in the 1s² orbital. the next two electron will go in the 2s orbital and the next 6 electron will go in the 2p orbital.

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8 0
3 years ago
What is the molar mass of CH4 (C=12.011 amu H = 1.008 amu)
never [62]

Answer:

16.05 amu

Explanation:

12.011 rounds to about 12.01 and 1.008 rounds to about 1.01 so when adding you'd do [12.01 + (1.01×4)]= 16.05

6 0
3 years ago
The compound 1-butene is modeled here. What would need to happen for molecules of this compound to transform into polybutene? A.
kompoz [17]
In order to form polymers, we need to chain molecules together. This involves making bonds between them.

Shifting H’s around doesn’t accomplish anything.

Forming more double bonds will have the opposite result, as it would make the molecules more stable and less likely to react with each other.

Adding oxygen to the molecule no longer makes it polybutene. That would likely result in the formation of some sort of ether, as hey would react to form a C-O-C Bond.

The only answer left is A. In order to form polyalkenes, we have to break a double bond so that it’s available to form more covalent bonds.

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4 0
3 years ago
Sodium carbonate reacts with silver nitrate according to the following balanced equation: Na2CO3 (s) + 2 AgNO3 (aq) → Ag2CO3 (s)
klemol [59]

Answer:

a) 2.01 g

Explanation:

  • Na₂CO₃ (s) + 2AgNO₃ (aq) → Ag₂CO₃ (s) + 2NaNO₃

First we <u>convert 0.0302 mol AgNO₃ to Na₂CO₃ moles</u>, in order to <em>calculate how many Na₂CO₃ moles reacted</em>:

  • 0.0302 mol AgNO₃ * \frac{1molNa_2CO_3}{2molAgNO_3}  = 0.0151 mol Na₂CO₃

So the remaining Na₂CO₃ moles are:

  • 0.0340 - 0.0151 = 0.0189 moles Na₂CO₃

Finally we <u>convert Na₂CO₃ moles into grams</u>, using its <em>molar mass</em>:

  • 0.0189 moles Na₂CO₃ * 106 g/mol = 2.003 g Na₂CO₃

The closest answer is option a).

8 0
3 years ago
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Anika [276]

Answer:

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Explanation:

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2 years ago
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