Answer:
h =
- r
Step-by-step explanation:
The question requires you to make h the subject of the formula.
S = 2πrh + 2πr²
subtract 2πr² on both sides.
S - 2πr² = 2πrh - 2πr² - 2πr²
S - 2πr² = 2πrh
Dividing both sides by 2πr
(S - 2πr²)/2πr = 2πrh/ 2πr
h =
- r
Answer:
Step-by-step explanation:
Given the following data;
Principal = $7,000
Interest = 3.5% = 3.5/100 = 0.035
To find the future value, we would use the compound interest formula;
Where;
A is the future value.
P is the principal or starting amount.
r is annual interest rate.
n is the number of times the interest is compounded in a year.
t is the number of years for the compound interest.
Substituting into the equation, we have;
Answer:

Step-by-step explanation:
Alrighty let's do this.
We know that formula for the Area of a triangle is:

They give us the area as
, so let's include it in the equation.

Now we reach a stage where we have 2 unknown variables! That means we can't solve it in its current state. So the idea you should have in cases like these where you have 2 or more unknown variables is, "Can I represent this one variable in terms of another variable?" In this case you can do exactly that. You can represent height in terms of length of the base. We are told the height of the triangle is 4 meters less than the base. That is telling us that 
So replace
in the equation with
.
You will now get:

Now we can work towards solving. Let's get simplifying.

bring everything to one side so we can make a quadratic and factor:

We get that
.
Since we need the height of the triangle we'll need to call back on what h is. We found earlier that
, so to find h, we just sub in our b value into that.

We find that 
Its a squared + xb squared = c squared so its 11 squared + 11 squared equals c squared. So I'm gonna take it down to the next step and say 11x11+ 11x11= c squared, then you end up with 121+121= c squared then you add those two and end up with 242= c squared, so then you find the square root of 242 so you should end up with 15.5 and the number goes on and on and on