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Ray Of Light [21]
3 years ago
9

What are the solutions of the equation (x−9)2=64?

Mathematics
1 answer:
maksim [4K]3 years ago
6 0

Answer:

17,1

Step-by-step explanation:

I just did this question on the benchmark

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Is x and x2 like terms or unlike terms​
babymother [125]

Like terms" are terms whose variables (and their exponents such as the 2 in x2) are the same. In other words, terms that are "like" each other. Note: the coefficients (the numbers you multiply by, such as "5" in 5x) can be different.

4 0
3 years ago
PLEASE HELP. WILL GIVE BRAINLIEST
KengaRu [80]

Answer:

x-intercepts = 1,2, and 4, y-intercept = -8

Step-by-step explanation:

x^3 - 7x^2 - 14x - 8 in factored form is equal to (x-1)(x-2)(x-4).

Solving for x-intercepts:

  • We are actually able to solve for all x-intercepts without the given factor. But since we are given one of the factors, our job becomes much easier.
  • Using synthetic division, or long division, we factor out the x-intercept 4. Which leaves us with the polynomial x^2 - 3x + 2.
  • From here we can separate the polynomial into two binomials.
  • x^2 - 3x + 2 = (x-1)(x-2). Giving us all 3 x-intercepts.
  • Using Descartes' rules we can identify before even starting the problem how many real x-intercepts there are (Not needed for this problem).

Solving for y-intercept:

  • The y-intercept is always the coefficient that does not have any assigned x-variables.
  • The coefficient is -8, thus the y-intercept.
  • If unsure of the y-intercept, you can always plug in x = 0. Solving for the y-intercept will give you the value of f(0).
  • If there is no coefficient, the y-intercept is equal to zero.
4 0
3 years ago
What is 9/14 x 2 1/3!!!!
pshichka [43]
The answer is 11
Explaination:
9/14 multiple both numbers by 3=27/42
Break 2 1/3 into 2 and 1/3
1/3 multiple both numbers but 14=14/42
27/42 x 14/42 keep number on the bottom the same
27x14= 378
Divide 378/42=9
Add the 2 from 2 1/3 to the nine
2+9=11
8 0
2 years ago
Read 2 more answers
Police estimate that​ 25% of drivers drive without their seat belts. If they stop 6 drivers at​ random, find the probability tha
Furkat [3]

Answer:

17.80% probability that all of them are wearing their seat belts.

Step-by-step explanation:

For each driver stopped, there are only two possible outcomes. Either they are wearing their seatbelts, or they are not. The drivers are chosen at random, which mean that the probability of a driver wearing their seatbelts is independent from other drivers. So we use the normal probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Police estimate that​ 25% of drivers drive without their seat belts.

This means that 75% wear their seatbelts, so p = 0.75

If they stop 6 drivers at​ random, find the probability that all of them are wearing their seat belts.

This is P(X = 6).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{6,6}.(0.75)^{6}.(0.25)^{0} = 0.1780

17.80% probability that all of them are wearing their seat belts.

3 0
3 years ago
Read 2 more answers
Find the outlier of the data set?<br> 40, 62, 47, 68, 12, 78, 49, 65, 49, 52, 63
ss7ja [257]
The outlier is gonna be 12
5 0
4 years ago
Read 2 more answers
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