Answer:
The sum of all exterior angles of BEGC is equal to 360° ⇒ answer F only
Step-by-step explanation:
* Lets revise some facts about the quadrilateral
- Quadrilateral is a polygon of 4 sides
- The sum of measures of the interior angles of any quadrilateral is 360°
- The sum of measures of the exterior angles of any quadrilateral is 360°
* Lets solve the problem
- DEGC is a quadrilateral
∵ m∠BEG = (19x + 3)°
∵ m∠EGC = (m∠GCB + 4x)°
∵ The sum of the measures of its interior angles is 360°
∴ m∠BEG + m∠EGC + m∠GCB + m∠CBE = 360
∴ (19x + 3) + (m∠GCB + 4x) + m∠GCB + m∠CBE = 360 ⇒ add the like terms
∴ (19x + 4x) + (m∠GCB + m∠GCB) + m∠CBE + 3 = 360 ⇒ -3 from both sides
∴ 23x + 2m∠GCB + m∠CBE = 375
∵ The sum of measures of the exterior angles of any quadrilateral is 360°
∴ The statement in answer F is only true
Answer:
y > 4
Step-by-step explanation:
2 (5y-4)>32
Divide each side by 2
2/2 (5y-4)>32/2
5y-4 > 16
Add 4 to each side
5y-4+4 > 16+4
5y > 20
Divide each side by 5
5y/5 > 20/5
y > 4
Well, you get the volume by multiplying the height, the width, and the length. So just work on it backwards.
2,830.5 divided by (9 times 18.5).
9 times 18.5 is 166.5. So that leaves us with 2,830.5 divided by 166.5, which is 17.
So, the answer is 17.
Answer:
10+3pi
Step-by-step explanation:
The perimeter of of the shaded region is
AC+CT+marcSBT+SA
*Finding AC
The diagonals of a rectangle are equal is measurement. Since RB is a radius of the circle, then RB is 6. Since AC and RB are both diagonals of the rectangle, then AC is also 6.
*Finding CT
CT=RT-RC where RC is the width of the rectangle
Also RT is a radius so we have that
CT=6-RC
*Finding marcSBT
The circumference of a whole circle is 2pi*r.
We have a quarter of this with r=6.
1/4*2pi(6)
1/4*12pi
3pi
*Finding SA
SA=RS-AR
RS is a radius of the circle and AR is the length of the rectangle.
So we have that this can be rewritten as
SA=6-AR
Let's put these parts together:
6+6-RC+3pi+6-AR
Simplifying:
18-RC-AR+3pi
18-(RC+AR)+3pi
18-8+3pi (Remember length plus width equal 8)
10+3pi
Answer:
y = mx + b is slope-intercept form of the linear equation.
y - y1 = m(x - x1) is point-slope form of the linear equation.
Ax + By = C (A ≥ 0) is standard form of the linear equation.
~~~~~~~~~~~
....
1
y – 5 = —— (x + 1)
3
1 1
y = —— x + —— + 5
3 3
1 16
(1) y = —— x + ——
3 3
Step-by-step explanation:
