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Mathematics

1 answer:

zvonat [6]2 years ago

6 0

Answer:

The IQR describes the middle 50% of values when ordered from lowest to highest. To find the interquartile range (IQR), first find the median (middle value) of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.

Step-by-step explanation:

You might be interested in

What is the equation of a line that has a slope of 2 and passes through the point (4,6) ?

natka813 [3]

Answer:

$y-6=2\,(x-4)$

or in slope y-intercept form :

$y=2x-2$

Step-by-step explanation:

The easiest way of find the answer for this is to use what is called the "point-slope" form of a line, because you are in fact given the value of the slope (m) and also a point $(x_0,y_0)$ it goes through:

$y-y_0=m\,(x-x_0)$

In our case the equation becomes:

$y-y_0=m\,(x-x_0)\\y-6=2\,(x-4)\\$

This can also be written in the slope-intercept form by solving for "y" and operating to remove the parenthesis:

$y-6=2\,(x-4)\\y=2x-8+6\\y=2x-2$

7 0

3 years ago

What is the equation of the line, in standard form, that passes through (4, -3) and is parallel to the line whose equation is 4

Dmitry_Shevchenko [17]

The equation is: 4x + y + a = 0

Point (4, -3) ⇒ x = 4 and y = - 3

⇒ 4 · 4 - 3 + a = 0

16 - 3 +a = 0

13 + a = 0

a = -13

Ansver: equation is: 4x + y - 13 = 0 OR 4x + y = 13

5 0

3 years ago

Read 2 more answers

As an introduction to probability, a student asked to roll a fair, six sided number cube seven times the results of those seven

frosja888 [35]

Using it's concept, the standard deviation of the data is of 3.742.

<h3>What are the mean and the standard deviation of a data-set?</h3>

The mean of a data-set is given by the sum of all values in the data-set, divided by the number of values.

The standard deviation of a data-set is given by the square root of the sum of the differences squared between each observation and the mean, divided by the number of values.

For this data-set, the mean is:

M = (1 + 4 + 4 + 4 + 4 + 6 + 5)/7 = 4.

Hence the standard deviation is:

$S = \sqrt{\frac{(1 - 4)^2 + (4 - 4)^2 + (4 - 4)^2 + (4 - 4)^2 + (4 - 4)^2 + (6 - 4)^2 + (5 - 4)^2}{7}} = 3.742$