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nekit [7.7K]
3 years ago
7

Ayudaaaaaaaaaaaaaaaaaa aaa aaa aaa Doy corona

Mathematics
1 answer:
zvonat [6]3 years ago
6 0

Answer:

The IQR describes the middle 50% of values when ordered from lowest to highest. To find the interquartile range (IQR), ​first find the median (middle value) of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.

Step-by-step explanation:

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Renee scores an average of 153 points in a game of bowling, and her points in a game of bowling are normally distributed. Suppos
Lelu [443]

Answer:

\sigma=\frac{175-153}{2}=11

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Let X the random variable that represent points in a game of bowling of a population, and for this case we know the distribution for X is given by:

X \sim N(153,unknown)  

Where \mu=153 and \sigma=?

We know that the value for Renee is X=175 and the z score obteined was Z=2.

Solution to the problem

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{X-\mu}{\sigma}

We are interested on the value of \sigma and we can solv for it:

z \sigma = X-\mu

\sigma=\frac{X-\mu}{z}

And replacing the values we have:

\sigma=\frac{175-153}{2}=11

 

5 0
3 years ago
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Ksju [112]
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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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6 0
3 years ago
I need help please ..
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Answer:

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Step-by-step explanation:

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3 0
4 years ago
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