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3 years ago

Please help!!!!!!!!!!!!!!!!

Mathematics

1 answer:

noname [10]3 years ago

6 0

Answer:

jajajajajajajajajajajqjajajqjajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajaja

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What statement best describes the solution of the system of the equations shown 2x-y=1

Aliun [14]

I’m pretty sure it’s B because you can put in any number and it could still have a difference of 1

8 0

3 years ago

According to the tables used by insurance companies, a 48-year old man has a 0.169% chance of

yarga [219]

Answer:

The expected value for the person buying the insurance is of -$48.

Step-by-step explanation:

Expected value:

0.169% = 0.00169 probability of earning the death benefit of $100,000, subtracting 217, 100000 - 217 = $99,783.

100 - 0.169 = 99.831% = 0.99831 probability of losing $217.

What is the expected value for the person buying the insurance?

$E = 0.00169*99783 - 0.99831*217 = -48$

The expected value for the person buying the insurance is of -$48.

5 0

3 years ago

Dione has 3 rolls of pennies containing 50 coins each, 4 rolls of nickels

ankoles [38]

Answer:

$94.50

Step-by-step explanation:

3(50)=150 $1.50

4(40)=160 160(5)=800 $8.00

5(50)=250 250(10)=2500 $25.00

6(40)=240 240(25)=6000 $60.00

60+25+8+1.5=$94.50

3 0

3 years ago

A patient is given a 100-milligram dosage of a drug that decays exponentially at a rate of 11% per hour. The doctor wants to kno

I am Lyosha [343]

Answer:

This is an example of exponential decay (somewhat similar to half-life).

If it decays at 11% per hour we can calculate its half-life by this formula:

half life = [ time • ln (2) ] ÷ ln (beginning amount ÷ ending amount)

where "ln" means natural log

half life =[ 1 hour * .69315] / ln (100 / 89)

half life =[.69315] / ln (1.1235955056)

half life =[.69315] / 0.11653381624

half life = 5.9481 hours

We need "lambda" "λ" (the decay constant) which equals

λ = ln(2) / half-life = .693147 / 5.9481 = 0.1165325062

Now we need a formula for the time required:

time = ln (Nt ÷ N0) ÷ -λ where No = beginning amount (100 milligrams) Nt = ending amount (15 milligrams)

time = ln (15 ÷ 100) ÷ -0.1165325062

time = ln (.15) / -0.1165325062

time = -1.8971199849 / -0.1165325062

time = 16.2797492885 hours

Source: https://www.1728.org/halflif2.htm

Step-by-step explanation:

4 0

3 years ago

J/k- 0.2k when j = 25 and K = 5

Lilit [14]

25/5-0.2*5=?
1.(25/5=5)
2.(5-0.2=4.8)
3.(4.8*5=24)
4. the answer is 24

Happy to Help!!! :) :)

3 0

3 years ago