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RUDIKE [14]
2 years ago
7

In a recent survey of 150 teenagers, 93 stated that they always wear their seat belt when they travel in a car. Assuming the dis

tribution is approximately normal, find the point estimate and standard error for the proportion of teenagers that always wear a seat belt when traveling in a car. Round your answers to two decimal places, as needed.
Mathematics
1 answer:
irinina [24]2 years ago
3 0

Answer:

Point estimate = 0.62

Step-by-step explanation:

Point estimate = x/n

Given

n is the sample size = 150

X = Those that wear their seat belt

X = 93

Point estimates = 93/150

Point estimates = 0.62

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If x varies directly with y and x = 3.5 when y = 14, find x when y = 18.
maks197457 [2]

Answer:

x = 4.5

Step-by-step explanation:

there's definitely other ways to solve this, but I used a proportion.

\frac{3.5}{x} = \frac{14}{18}

Then you can make this equation:

14x = 3.5 * 18

I solved for it and got 4.5 .

5 0
3 years ago
Using the functions presented in the example, how much can Cam expect to earn if he sells all the corn produced on 1.5 acres?
12345 [234]

Answer:

Cam expect to earn if he sells all the corn produced on 1.5 acres is $8725.

Step-by-step explanation:

Given : C(a)=7500a-1500, M(C)=0.9C- 50  and  M(C(a))=6750a-1400

To find : How much can Cam expect to earn if he sells all the corn produced on 1.5 acres?

Solution :  

C(a)=7500a-1500

Substitute a=1.5,

C(1.5)=7500(1.5)-1500

C(1.5)=11250-1500

C(1.5)=9750

Now, taking function M(C)=0.9C- 50

Substitute C=9750,

M(9750)=0.9(9750)- 50

M(9750)=8775- 50

M(9750)=8725

Now, taking function M(C(a))=6750a-1400

Substitute a=1.5,

M(C(1.5))=6750(1.5)-1400

M(C(1.5))=10125-1400

M(C(1.5))=8725

Therefore, Cam expect to earn if he sells all the corn produced on 1.5 acres is $8725.

8 0
3 years ago
Factor 6y 2 - 48 + 42y.<br><br> (6y + 8)(y - 6)<br> 6(y + 8)(y - 1)<br> 6(y - 1)(y - 7)
astraxan [27]

Answer:

6 (y + 8) (y - 1)

Step-by-step explanation:

Factor the following:

6 y^2 + 42 y - 48

Factor 6 out of 6 y^2 + 42 y - 48:

6 (y^2 + 7 y - 8)

The factors of -8 that sum to 7 are 8 and -1. So, y^2 + 7 y - 8 = (y + 8) (y - 1):

Answer: 6 (y + 8) (y - 1)

PS: it's really helpful to pose the question correctly 6 y^2 + 42 y - 48  NOT

6y 2 - 48 + 42y

3 0
4 years ago
Read 2 more answers
A tracksuit top costs £12.75 and matching tracksuit bottoms cost £9.50, how much does the tracksuit cost altogether?
andrey2020 [161]

Step-by-step explanation:

£22.25 pls mark brainliest thanks

5 0
4 years ago
Which expression is equivalent to ( 4mn / m^-2n^6)^-2a. n^6 / 16m^8b. n^10 / 16m^6c. n^10 / 8m^8d. 4m^3 / n^8?
Eva8 [605]

\huge{(} \small{\frac{4mn}{ {m}^{ - 2} {n}^{6}  }}  \huge{) } \small{{}^{  {}^{ {}^{ {}^{ - 2} } } } }\\  \\  \\ \huge{(} \small{   \frac{4 \times m {}^{1}  \times n {}^{1} }{ {m}^{ - 2} \times  {n}^{6}  }}  \huge{)} \small{^{  {}^{ {}^{ {}^{ - 2} } } }} \\  \\  \\  \huge{(} \small{4 \times  {m}^{1 - ( - 2)}  \times  {n}^{1 - 6}} \huge{)} \small{ {}^{  {}^{ {}^{ {}^{ - 2} } } } } \\  \\  \\   \huge{(} \small{ 4 \times  {m}^{1 + 2}  \times  {n}^{ - 5} } \huge{)} \small{ { }^{ {}^{  {}^{  {}^{ - 2} } }  } } \\  \\  \\ \small{  {(4)}^{ - 2} \times  ({m}^{3} ) ^{ - 2} \times  {(n{}^{ - 5} )}^{ - 2}    } \\  \\  \\  \frac{1}{ {4}^{2} }  \times  {m}^{ - 6}  \times  {n}^{ 10}  \\  \\  \\  \frac{1}{16}  \times  \frac{1}{ {m}^{6} }  \times  {n}^{10}  \\  \\  \\  \frac{ {n}^{10} }{16{m}^{6} }







\text{ Hence, option B is correct }
7 0
4 years ago
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