The answer is A,
In a function, an x value can only be paired with one y value.
However, a y value and have multiple different x values, for example when you graph a constant/horizontal line.
Answer:
13/12 or 1 1/12
Step-by-step explanation:
First you would convert the 1/6 to 2/12 then add them like normal to get 13/12.
Hope this helps :
You need to isolate p:
1.4 divided by 0.7 = 0.7p divided by 0.7 (this eliminates 0.7)
2 = p
Answer:
x = 2
Step-by-step explanation:
Taking antilogs, you have ...
2³ × 8 = (4x)²
64 = 16x²
x = √(64/16) = √4
x = 2 . . . . . . . . (the negative square root is not a solution)
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You can also work more directly with the logs, if you like.
3·ln(2) +ln(2³) = 2ln(2²x) . . . . . . . . . . . write 4 and 8 as powers of 2
3·ln(2) +3·ln(2) = 2(2·ln(2) +ln(x)) . . . . use rules of logs to move exponents
6·ln(2) = 4·ln(2) +2·ln(x) . . . . . . . . . . . . simplify
2·ln(2) = 2·ln(x) . . . . . . . . . . . subtract 4ln(2)
ln(2) = ln(x) . . . . . . . . . . . . . . divide by 2
2 = x . . . . . . . . . . . . . . . . . . . take the antilogs
