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mr Goodwill [35]
3 years ago
8

g The tensile 0.2 percent offset yield strength of AISI 1137 cold-drawn steel bars up to 1 inch in diameter from 2 mills and 25

heats is reported as follows: S y 93 95 97 99 101 103 105 107 109 111 f 19 25 38 17 12 10 5 4 4 2 where y S is the class midpoint in kpsi and f is the number in each class. Presuming the distribution is normal, what is the yield strength exceeded by 99 percent of the population
Mathematics
1 answer:
Vitek1552 [10]3 years ago
3 0

Answer:

107.50

Step-by-step explanation:

Given the following :

Midpoint (S)____F

S y 93 95 97 99 101 103 105 107 109 111 f 19 25 38 17 12 10 5 4 4 2

Calculating the mean and standard deviation using a calculator :

The mean(m) of the data above = 98.12

Standard deviation (sd) = 4.02

Proportion = 99% of population

From z table = 2.33

Using :

Zscore =(x - m) / sd

2.33 = (x - 98.12) / 4.02

2.33 * 4.02 = x - 98.12

9.3666 = x - 98.12

9.3666 + 98.12= x

x = 107.4866

X = 107.50

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Find the maximum and minimum values attained by f(x, y, z) = 5xyz on the unit ball x2 + y2 + z2 ≤ 1.
Allushta [10]
Check for critical points within the unit ball by solving for when the first-order partial derivatives vanish:
f_x=5yz=0\implies y=0\text{ or }z=0
f_y=5xz=0\implies x=0\text{ or }z=0
f_z=5xy=0\implies x=0\text{ or }y=0


Taken together, we find that (0, 0, 0) appears to be the only critical point on f within the ball. At this point, we have f(0,0,0)=0.

Now let's use the method of Lagrange multipliers to look for critical points on the boundary. We have the Lagrangian

L(x,y,z,\lambda)=5xyz+\lambda(x^2+y^2+z^2-1)

with partial derivatives (set to 0)

L_x=5yz+2\lambda x=0
L_y=5xz+2\lambda y=0
L_z=5xy+2\lambda z=0
L_\lambda=x^2+y^2+z^2-1=0

We then observe that

xL_x+yL_y+zL_z=0\implies15xyz+2\lambda=0\implies\lambda=-\dfrac{15xyz}2

So, ignoring the critical point we've already found at (0, 0, 0),


5yz+2\left(-\dfrac{15xyz}2\right)x=0\implies5yz(1-3x^2)=0\implies x=\pm\dfrac1{\sqrt3}
5xz+2\left(-\dfrac{15xyz}2\right)y=0\implies5xz(1-3y^2)=0\implies y=\pm\dfrac1{\sqrt3}
5xy+2\left(-\dfrac{15xyz}2\right)z=0\implies5xy(1-3z^2)=0\implies z=\pm\dfrac1{\sqrt3}

So ultimately, we have 9 critical points - 1 at the origin (0, 0, 0), and 8 at the various combinations of \left(\pm\dfrac1{\sqrt3},\pm\dfrac1{\sqrt3},\pm\dfrac1{\sqrt3}\right), at which points we get a value of either of \pm\dfrac5{\sqrt3}, with the maximum being the positive value and the minimum being the negative one.
5 0
3 years ago
Question is attached
rodikova [14]

9514 1404 393

Answer:

  x = 12

  perimeter = 124

Step-by-step explanation:

The midline RS is half the length of MN, so we have ...

  2×RS = MN

  2(x +3) = 5x -30

  2x +6 = 5x -30

  36 = 3x . . . . . . . . . add 30-2x

  12 = x . . . . . . . . . . divide by 3

__

The length RS is then ...

  RS = x +3 = 15

and the perimeter of QRS is ...

  P(QRS) = QR +RS +SQ = 25 +15 +22 = 62

The perimeter of QRS is half the perimeter of MNP, so ...

  P(MNP) = 2×P(QRS) = 2×62 = 124

The perimeter of ΔMNP = 124.

8 0
2 years ago
What is the solution to the inequality 6 − 2x < 4?
slega [8]
X>1 if that helps with your problem
4 0
2 years ago
PLEASE ANSWER ASAP FOR BRAINLEST WITH WORK!!!!!!!!!!!!!!!
alexira [117]

Answer:

The answer is 43 because 600/14 = 42.8571429 rounded to the nearest whole number is 43.

Step-by-step explanation:

4 0
2 years ago
Katie stop erasing my questions im just trying to help idxiot
Anna007 [38]

Answer:

HEY

Step-by-step explanation:

i think so u also dont know the que

8 0
3 years ago
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