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MissTica
3 years ago
11

PLEASE HELP Find the area of the rectangle, to the nearest hundredth, with a base of 5 inches and a height = 2.5 inches. Type a

numerical answer in the space provided. Do not include units or spaces in your answers.
a0.
Mathematics
1 answer:
il63 [147K]3 years ago
5 0

Answer:

The area of a rectangle with a width of 5 inches, and a height of 2.5 inches, would have an area 12.5 inches!

Step-by-step explanation:

To find the area of a rectangle, simply multiply the width (W) by the length (L) to find the area (A) of the rectangle.

A = W x L

A = 5 inches x 2.5 inches

A = 12.5 inches

Hope this helps! :)

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What’s the volume of a cylinder with a radius of 6ft and height of 14ft? pls show work
Daniel [21]

Answer:

<em><u>Given </u></em><em><u>-</u></em>

  • <em><u>radius </u></em><em><u>of </u></em><em><u>cylinder </u></em><em><u>=</u></em><em><u> </u></em><em><u>6</u></em><em><u> </u></em><em><u>ft</u></em>
  • <em><u>height </u></em><em><u>of </u></em><em><u>cylinder </u></em><em><u>=</u></em><em><u> </u></em><em><u>1</u></em><em><u>4</u></em><em><u> </u></em><em><u>ft</u></em>

Now ,

volume = \pi \: r {}^{2} h \\  =  >  \frac{22}{\cancel{7}}  \times 6 \times\cancel{ 14} \\  \\  =  > 22 \times 6 \times 2 \\  =  > 264 \: ft {}^{3}

hope helpful~

5 0
2 years ago
Make U the subject of the formula <br> D = ut + kt2
natali 33 [55]

Remark

I'm going to interpret this equation as

D = ut + kt²  The only difference is the 2.

Solution

Subtract kt² from both sides.

D - kt² = ut   Now divide by u on both sides.

\dfrac{D - kt^2}{t} = \dfrac{ut}{t}

The t's cancel out. on the right.  You are left with u on the right.

\dfrac{D - kt^2}{t} =\text{u}


6 0
3 years ago
Solve for x.<br><br> (x−2)^2+2=38<br><br> x= ___ or x= ___
Elan Coil [88]

Answer:

x  \: = \:  \boxed{ \bold{  - 4  }}\:    \:    \text{or} \:   \: x \:  = \:  \boxed{ \bold{ 8}}

Step-by-step explanation:

(x \:  -  \: 2 {)}^{2}  \:  +  \: 2 \:  =  \: 38

{x}^{2}  \:  -  \: 4x \:  +  \: 4 \:  +  \: 2 \:  =  \: 38

{x}^{2}  \:  -  \: 4x \:  +  \: 6 \:  =  \: 38

{x}^{2}  \:  -  \: 4x \:  +  \: 6 \:  -  \: 38 \:  =  \: 0

{x}^{2}  \:  +  \: 4x \:  -  \: 8x \:  -  \: 32 \:  =  \: 0

x \:  \times  \: (x \:  +  \: 4) \:  -  \: 8(x \:  +  \: 4) \:  =  \: 0

(x \:  +  \: 4) \:   \times  \: (x \:  -  \: 8) \:  =  \: 0

  • When it happens that the product of the factors is the same as zero. It is divided into two possible cases.

x \:  +  \: 4 \:  =  \: 0 \\ x \:  -  \: 8 \:  =  \: 0

  • We solve the two equations:

x \:  =  \:  - 4 \\ x \:  =  \: 8

<h2>Answer: </h2>

x \:  =  \:  - 4 \\ x \:  =  \: 8

<h3><em><u>MissSpanish</u></em></h3>

6 0
2 years ago
Use the diagram on the right. How many planes contain both the line and the point
Aloiza [94]

Part (a)

<h3>Answer: 0</h3>

-------------------

Explanation:

Point P is part of 3 planes or faces of this triangular prism:

  • plane PEF (the front slanted plane)
  • plane PEH (the left triangular face)
  • plane PHG (the back rectangular wall)

Notice how each three letter sequence involves "P", though this isn't technically always necessary. I did so to emphasize how point P is involved with these planes.

Each of the three planes mentioned do not involve line FG

  • Plane PEF only deals with point F
  • Plane PEH doesn't have any of F or G involved
  • plane PHG only involves G

So there are no planes that contain line FG and point P.

==================================================

Part (b)

<h3>Answer: 0</h3>

-------------------

Explanation:

It's the same idea as part (a) earlier. The planes involving point G are

  • plane GQF  (triangular face on the right)
  • plane GFE (bottom rectangular floor)
  • plane GHP (back rectangular wall)

None of these planes have line EP going through them.

As an alternative, we could reverse things and focus on all of the planes connected to line EP. Those 2 planes are

  • plane PEH (triangular face on the left)
  • plane PEF (front slanted rectangular face)

None of these planes have point G located in them.

8 0
3 years ago
Guys omg please someone answer this asap this is due tmmr
MrRissso [65]

Answer:

First, break the shape into smaller shapes.

Bigger rectangle: 5m, 8m

Thin rectangle: 7m, 3m

Thinner rectangle: 8m, 2m

We will call the bigger rectangle <u>B</u>, the thin rectangle <u>R</u>, and the thinner rectangle <u>r</u>.

Step-by-step explanation:

B = 8 • 5 = 40

R = 7 • 3 = 21

r = 2 • 8 = 16

Add the areas together:

40 + 21 + 16 = 77

Therefore, the area is <u>77 meters.</u>

4 0
2 years ago
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