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3 years ago

A culture started with 2000 bacteria after 5 hours it grew to 2600

1 answer:

3 0

P(t) = P₀ e^(kt)

Where P₀ is the initial population, 
P(t) is the population after "t" time. 
t is your rate (can be hours, days, years, etc. in this case, hours) 
k is the growth constant for this particular problem. 

So using the information given, solve for k: 

P₀ = 2000 
P(4) = 2600 

P(t) = P₀ e^(kt) 
2600 = 2000e^(k * 4) 
1.3 = e^(4k) 

Natural log of both sides: 

ln(1.3) = 4k 
k = ln(1.3) / 4 

Now that we have a value for "k", use that, the same P₀, then solve for P(17): 

P(t) = P₀ e^(kt) 
P(17) = 2000 e^(17ln(1.3) / 4) 

Using a calculator to get ln(1.3) then to simplify from there, we get: 

P(17) ≈ 2000 e^(17 * 0.262364 / 4) 
P(17) ≈ 2000 e^(4.460188 / 4) 
P(17) ≈ 2000 e^(1.115047) 
P(17) ≈ 2000 * 3.0497 
P(17) ≈ 6099.4 

Rounded to the nearest unit: 

P(17) ≈ 6099 bacteria hope i could help =)))

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A stack of seven different cards are shuffled and spread out face down if three cards are turned face up how many different thre

Anton [14]

<h2>Answer:35 ways</h2>

Step-by-step explanation:

$^nC_{k}$ is the number of ways of choosing $k$ distinct objects from a lot of $n$ distinct objects.

In the given question,

$n=7\\k=3\\$

$^nC_{k}=\frac{n!}{(n-k)!k!}$

So, $^7C_{3}=\frac{7!}{3!4!}=\frac{210}{6}=35$

So,there are $35$ ways in which three distinct cards can be selecte from seven distinct cards.

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3 years ago

Given f(x) = 6x^4 – 10x^3 + 40x – 50, find f(2)

ASHA 777 [7]

F(x)=6x^4-10x^3+40x-50, plug 2 in for x
f(2)=6(2)^4-10(3)^3+40(2)-50
f(2)=12^4-30^3+80-50
f(2)=20735-27,000+80-50
f(2)=-6,235

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3 years ago

rosijanka [135]

F=ma so 160N=20kg*8m/s

160 N is the answer

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3 years ago

Help please will mark brainliest answer!!! ASAP!!!

dezoksy [38]

P = principal (initial amount), r = rate of interest, and t = time

So, A = 3000(1+0.025)^4

Answer: $3,311.44 (approximately)

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3 years ago

An illusionist needs up to 10 volunteers for a show. The illusionist needs no fewer than 4 female volunteers. Let x represent th

Tems11 [23]

Answer:

FIRST OPTION.

THIRD OPTION.

FIFTH OPTION.

Step-by-step explanation:

Let be "x" the number of of female volunteers and "y" the number of male volunteers.

You need to remember the meaning of the inequalities symbols:

: Less than.

$>$ : Greater than.

$\leq$ : Less than or equal to.

$\geq$ : Greater than or equal to.

In this case you know that the illusionist needs up to 10 volunteers, which indicates that the total number of volunteers can be less than or equal to 10 people. The inequality that represents this is:

$x+y\leq 10$

According to the exercise, the illusionist needs no fewer than 4 female volunteers. This means that number of female volunteer must be greater than or equal to 4:

$x\geq 4$

Since the number of female volunteers could be 10 (Because can be greater than 4), it could not be male volunteers. This means that:

$y\geq 0$

7 0

4 years ago

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