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ivanzaharov [21]
2 years ago
13

The graph of r = -10 cos θ has which of the following characteristics?

Mathematics
1 answer:
Ronch [10]2 years ago
8 0

Step-by-step explanation:

If we convert

r =  - 10 \cos(x)

to a Cartesian equation,

{r}^{2}  =  - 10 r \: \cos(x)

{x}^{2}  +  {y}^{2}  =  - 10x

{x}^{2}  + 10x +  {y}^{2}  = 0

{x}^{2}  + 10x + 25 +  {y}^{2}  = 25

(x + 5) {}^{2}  +  {y}^{2}  = 25

So we have a circle with center (-5,0), with a diameter of 10.

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Hey what's the answer ?<br><br><img src="https://tex.z-dn.net/?f=%28x%20-%20y%29" id="TexFormula1" title="(x - y)" alt="(x - y)"
Varvara68 [4.7K]

Answer:

<em> </em><em>-</em><em>1</em>

Step-by-step explanation:

<em>here's</em><em> your</em><em> solution</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>The </em><em>value</em><em> of</em><em> x</em><em> </em><em>=</em><em> </em><em>1</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>The </em><em>value</em><em> of</em><em> </em><em>y </em><em>=</em><em> </em><em>2</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>we </em><em>need</em><em> to</em><em> find</em><em> </em><em>(</em><em> </em><em>x </em><em>-</em><em> </em><em>y)</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>so,</em><em> </em><em>put </em><em>the </em><em>value </em><em>of </em><em>above</em><em> </em><em>variables</em><em> </em><em>in </em><em>it</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>hence</em><em>,</em><em> </em><em>(</em><em>1</em><em> </em><em>-</em><em> </em><em>2</em><em>)</em><em> </em><em>=</em><em> </em><em>-</em><em> </em><em>1</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>-</em><em> </em><em>1</em><em> </em><em>is </em><em>correct</em><em> answer</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>hope</em><em> it</em><em> helps</em>

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Step-by-step explanation:

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