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3 years ago

A square has a perimeter of 4 cm. What is the length of each side?

Mathematics

2 answers:

MAXImum [283]3 years ago

3 0

Answer:

1 cm

Step-by-step explanation:

Since the perimeter is 4 cm and all the sides of the square have the same length, each side must be 1 cm long.

The area of that square is 1 cm x 1 cm, which is 1 cm2.

Wittaler [7]3 years ago

3 0

Step-by-step explanation:

since the all side is same,the side length is just 1 cm. And the area is just the side length square =1cmsquare× 1 cm

= ans is 1cm^2

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I do not know how to do this need help

Diano4ka-milaya [45]

Remark

First of all you have to declare the meaning of g(f(x)) After you have done that, you have to make the correct substitution.

Givens

f(x) = 4x^2 + x + 1

g(x) = x^2 - 2

Discussion

What the given condition g(f(x)) means is that you begin with g(x). Write down g(x) = x^2 - 2

Wherever you see an x on either the left or right side of the equation, you put fix)

Then wherever you see f(x) on the right you put in what f(x) is equal to.

Solution

g(x) = x^2 - 2

g(f(x)) = (f(x))^2 - 2

g(f(x)) = [4x^2 + x + 1]^2 - 2

f(x)^2 =

4x^2 + x + 1

4x^2 + x + 1

16x^4 + 4x^3 + 4x^2

4x^3 + x^2 + x

4x^2 + x + 1

16x^4 + 8x^3 + 9x^2 + 2x + 1

Answer

g(f(x)) = 16x^4 + 8x^3 + 9x^2 + 2x + 1 - 2

g(f(x)) = 16x^4 + 8x^3 + 9x^2 + 2x - 1

5 0

3 years ago

If you roll two fair six-sided dice, what is the probability that both dice show an odd number?

OLEGan [10]

Answer:

1/4

Step-by-step explanation:

Both dice have odd numbers 1, 3, 5. The chances of getting an odd number on each number is 3/6

The probability of getting odd numbers on both is:

3/6 ⋅ 3/6 = 9/36 = 1/4

5 0

3 years ago

Read 2 more answers

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guajiro [1.7K]

Answer:

Solve for x by simplifying both sides of the equation, then isolating the variable.x≈−0.00413995,1.6090059

Step-by-step explanation:

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3 years ago

Read 2 more answers

A survey on British Social Attitudes asked respondents if they had ever boycotted goods for ethical reasons (Statesman, January

Blababa [14]

Answer:

a) 27.89% probability that two have ever boycotted goods for ethical reasons

b) 41.81% probability that at least two respondents have boycotted goods for ethical reasons

c) 41.16% probability that between 3 and 6 have boycotted goods for ethical reasons

d) The expected number is 2.3 and the standard deviation is 1.33.

Step-by-step explanation:

We use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

23% of the respondents have boycotted goods for ethical reasons.

This means that $p = 0.23$

a) In a sample of six British citizens, what is the probability that two have ever boycotted goods for ethical reasons?

This is P(X = 2) when n = 6. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{6,2}.(0.23)^{2}.(0.77)^{4} = 0.2789$

27.89% probability that two have ever boycotted goods for ethical reasons

b) In a sample of six British citizens, what is the probability that at least two respondents have boycotted goods for ethical reasons?

Either less than two have, or at least two. The sum of the probabilities of these events is decimal 1. So

$P(X < 2) + P(X \geq 2) = 1$

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

$P(X = 0) = C_{6,0}.(0.23)^{0}.(0.77)^{6} = 0.2084$

$P(X = 1) = C_{6,1}.(0.23)^{1}.(0.77)^{5} = 0.3735$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.2084 + 0.3735 = 0.5819$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.5819 = 0.4181$

41.81% probability that at least two respondents have boycotted goods for ethical reasons

c) In a sample of ten British citizens, what is the probability that between 3 and 6 have boycotted goods for ethical reasons?

Now n = 10.

$P(3 \leq X \leq 6) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)$

$P(X = 3) = C_{10,3}.(0.23)^{3}.(0.77)^{7} = 0.2343$

$P(X = 4) = C_{10,4}.(0.23)^{4}.(0.77)^{6} = 0.1225$

$P(X = 5) = C_{10,5}.(0.23)^{5}.(0.77)^{5} = 0.0439$

$P(X = 6) = C_{10,6}.(0.23)^{6}.(0.77)^{4} = 0.0109$

$P(3 \leq X \leq 6) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.2343 + 0.1225 + 0.0439 + 0.0109 = 0.4116$

41.16% probability that between 3 and 6 have boycotted goods for ethical reasons

d) In a sample of ten British citizens, what is the expected number of people that have boycotted goods for ethical reasons? Also find the standard deviation.

$E(X) = np = 10*0.23 = 2.3$

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{10*0.23*0.77} = 1.33$

The expected number is 2.3 and the standard deviation is 1.33.

5 0

3 years ago

Complete the point slope equation of the line through(-1,-10)and(5,2). y-6=

Lynna [10]

Answer:

Step-by-step explanation:

The point-slope of an equation of a line:

$y-y_1=m(x-x_1)$

m - slope

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the poinys (-1, -10) and (5, 2). Substitute:

$m=\dfrac{2-(-10)}{5-(-1)}=\dfrac{12}{6}=2$

Put the value of the slope and the coordinateso f the point (5, 2), to the equation of a line:

$y-2=2(x-5)$

In the question we have y - 6 = ...

Therefore

$y-2=2(x-5)$ subtract 4 from both sides

$y-6=2(x-5)-4$ use the distributive property

$y-6=2x-10-4$

$y-6=2x-14$ distributive

$y-6=2(x-7)$

5 0

4 years ago