Group and factor
undistribute then undistribute again
remember
ab+ac=a(b+c)
this is important
6d^4+4d^3-6d^2-4d
undistribute 2d
2d(3d^3+2d^2-3d-2)
group insides
2d[(3d^3+2d^2)+(-3d-2)]
undistribute
2d[(d^2)(3d+2)+(-1)(3d+2)]
undistribute the (3d+2) part
(2d)(d^2-1)(3d+2)
factor that difference of 2 perfect squares
(2d)(d-1)(d+1)(3d+2)
77.
group
(45z^3+20z^2)+(9z+4)
factor
(5z^2)(9z+4)+(1)(9z+4)
undistribuet (9z+4)
(5z^2+1)(9z+4)
Answer:
Step-by-step explanation:
-4 + (5+6/ -6 × 5) -2
Solve the brackets first!
-4 + (11/ -30) -2
Add the -4 and -2
-6 + (-11/30)
[If you meant -2 multiplied by (-11/30) then , something like this, If not then continue after the bracket!:
-4 + (11/15)
(-60+11)/15
-49/15 Answer ]
Now,
-6 -11/30
(-180-11)/30
-191/30
Hope this helps!
Please mark brainliest! Would really appreciate!
Answer:
1 e
2 c
3 d
4 a
5 b
Step-by-step explanation:
Hope this help
Answer:
A= 4*9
Step-by-step explanation:
A = b*h
A= 4*9
=36
