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vazorg [7]
2 years ago
14

1. Evaluate the following numerical expressions. Problem Set a. 2+(-3) +7 b. )-4-1 d. -10 = 2 + 3 C. Ni 2x2 e. (8) + 2 f. 3+(-4)

-1 2. Which expressions from Exercise 1 are equal?​
Mathematics
1 answer:
jek_recluse [69]2 years ago
7 0

Answer:

A equals 12

B equals 3

C equals 3+2+(-5)

E equals 4 NI

F equals -7+(-12)=19

Step-by-step explanation:

For A, you have to do the parenthesis first. I did 2+(-3) which equals -5. Then, I added the 7 to the five and got 12. The reason that it is not 12 is because the +7 is greater than the -5.

For B, I got -3 because -4 - (-1) equals 3. The reason that it is three is because when you look at the positive negative chart, you can see that negative and negative equal positive. So, the answer would be 3.

For E, I got 4 NI because when I multiplied the 2*2 I got 4 then you add the numerals Ni. I am not 100% on this problem, that is kind of my guess.

Finally for F, I got 19. My equation above explains it. Once again, you have to add the parenthesis first, so, -7+(-12) equals 19. Like I said above. If you look at the negative positive chart, the number would be positive because both numbers are negative.

I forgot C above, so here it is. For C, I got the equation above by putting the numbers together. For instance, in the problem on the side, for C, it says -10=3+2. If you just add 3+2, you are going to get 5. I added negative five to it and there you go, you get negative ten.

The first and second problems are equal because 3 goes into 12 equally.

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garik1379 [7]

The question was incomplete. Please find full content below.

Which function is the inverse of

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if the domain of f(x) is x ≥ 0?

The inverse funtion of the given function is given by

\mathbf{f(x)=\sqrt{x+16}}

where the domain is x ≥ -16.

Given the function is,

f(x) =x^2-16

Let, y = f(x)

y = x^2-16

Adding 16 to both sides we get,

y + 16 =  {x}^{2}  - 16 + 16

{x}^{2}  = y + 16

Now, square rooting to both sides we get, since x ≥ 0

\sqrt{x^2}=\sqrt{y+16}

x=\sqrt{y+16}

f^{-1}(y)=\sqrt{y+16}

Hence substituting x in place of y,

f^{-1}(x)=\sqrt{x+16}

Above function is the required inverse function where the domain of that is given by, x ≥ -16.

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Answer:

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