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Ratling [72]
3 years ago
13

The length of a rectangle is 3x - 5 in and the width is 2x inches what is the area of the rectangle

Mathematics
1 answer:
77julia77 [94]3 years ago
6 0

Answer:

A = L * W

A = (3x-5) * 2x

A = 6x² - 10x



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Can you help me please​
Volgvan
D
Area of a circle is: 兀r✖️r, so 4.1m ➗2 = 2.05, 2.05✖️2.05 = 4.2025
3 0
2 years ago
-y=1/2x+2 in standard form
IceJOKER [234]

Answer:

Full answer is in the media.Good luck.

6 0
3 years ago
What is the area of this composite figure?
jek_recluse [69]

Answer:

7.14 in. sq

Step-by-step explanation:

First find the area of the square; 2x2=4

Now find the area of the semi-circle; radius = 1.    

1 squared= 1 Now multiply by 3.14 which equals 3.14

Now divide by 2 because it's a semi-circle, you get 1.57.

Multiply 1.57 by 2 because you have 2 semi-circles, the would equal 3.14

Add 4+3.14 and you get 7.14

The area of the composite figure is 7.14 in. sq

7 0
3 years ago
Is (x-3) a factor of f(x) = x^2 - 32?
Leokris [45]

Answer:

No

Explanation:

Here, we want to use the factor theorem to check if the given linear expression is a factor of the binomial

Now, according to the factor theorem, a factor of a polynomial would leave no remainder when divided by it

Mathematically, it means when we substitute the factor value into the polynomial, it is expected that the remainder is zero is the substituted is a factor of the polynomial

We set x-2 to zero:

\begin{gathered} \text{ x-2 = 0} \\ x\text{ = 2} \end{gathered}

Now, we substitute 2 into the polynomial as follows:

f(2)\text{ = }2^2-32\text{ = 4-32 = -28}

There is a remainder of -28 and thus, the linear factor is not a factor of the binomial

3 0
1 year ago
What are the total amount of choices possible if an individual is to create a 4 digit password using the digits 0 through 9 incl
qwelly [4]

9000 ways to create 4-digit passwords using digits from 0 to 9 that the first character can't be 0, but not using the digit 0 as the first character.

We have to see how many different 4-digit passwords we can create by using digits from 0 to 9, such that the first character can't be 0.

<h3>What is the combination?</h3>

Each of the different groups or selections can be formed by taking some or all of a number of objects, irrespective of their arrangments is called a combination.

Here we have 4 selections.

Now let's find the number of options for each of these:

First character = 9 options {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

Second character = 10 options {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

Third character = 10 options {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

Fourth character = 10 options {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

The total number of different combinations is just the product of these 4 numbers:

C = 9×10×10×10 = 9,000

So, we can conclude that the correct option is D.

If you want to learn more about combinations visit here;

brainly.com/question/2280026

4 0
2 years ago
Read 2 more answers
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