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Semenov [28]
3 years ago
14

Express decimal as a fraction 8.25

Mathematics
1 answer:
aksik [14]3 years ago
3 0

Answer:

33/4

Step-by-step explanation:

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whitney is training to ride her bicycle in a big race. The table below shows hiw many miles she rides each day of one week​
hoa [83]

Answer: C (24.5 miles more)

Step-by-step explanation:

on Friday she rode 42.4 miles

on Tuesday she rode 17.9 miles

you just subtract Tuesday’s miles from Friday’s miles

42.4 - 17.9 = 24.5

so, C

7 0
4 years ago
Find m angle ABC <br> I really need the answer to this
damaskus [11]
To find <ABC, the first thing you would need to do is to find angle DBA and the value of x

As <DBE is a right angle, <DBE is on the same straight line as well,meaning that it would be 90° , a right angle as well.

It also mean that the total sum of the angles unknown would be 90°

To find x,we need to set up an equation:
(2x+14)+ (x+7) = 90
3x+21 = 90
3x = 69
x = 23

Thus,<ABC would be
(23)+7
=30°

Hope it helps!
7 0
3 years ago
Read 2 more answers
I NEED HELP FAST ILL GIVE BRAINLIEST IF CORRECT!
klio [65]

Answer:

1548ft

Step-by-step explanation:

V=lwh

V=(10)(3)(6)=180

V=(19)(12)(6)=1368

V=180+1368=1548

<em>plz mark me brainliest.</em> :)

7 0
3 years ago
How to say 119,000,003 in two other ways?
Sergio039 [100]
You can say it in word form or expanded form
7 0
3 years ago
In a sample of 41 temperature readings taken from the freezer of a restaurant, the mean is 29.7 degrees and the population stand
yKpoI14uk [10]

Answer: =(29.1596\text{ degrees},\ 30.2404\text{ degrees})

Step-by-step explanation:

Given: Sample size: n = 41

Sample mean \overline{x}= 29.7 degrees

Population standard deviation \sigma=2.7 degrees

Confidence level (c) =  80% =0.80

Significance level (a) = 1- c = 1-0.80 = 0.20

z-score for 80% confidence level : z = 1.2816   [from z-table]

Confidence level for population mean :-

\overline{x}\pm z\dfrac{\sigma}{\sqrt{n}}

=29.7\pm ( 1.2816)\dfrac{2.7}{\sqrt{41}}

=29.7\pm ( 1.2816)\dfrac{2.7}{6.403124}

=29.7\pm ( 1.2816)(0.42167)

=29.7\pm 0.5404

=(29.7-0.5404,\ 29.7+0.5404)

=(29.1596,\ 30.2404)

Hence, 80% confidence interval for the temperatures in the freezer =(29.1596\text{ degrees},\ 30.2404\text{ degrees})

7 0
3 years ago
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