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ch4aika [34]
3 years ago
5

There are 2.2 pounds in a kilogram. There are 907.2 kilograms in a ton . If an animal weighs 3 tons , how many pounds does that

animal weigh ?
Mathematics
1 answer:
Olin [163]3 years ago
4 0
5,987.52 lbs

907.2 • 3 = 2,721.6 kg
2.2lbs=1kg
2.2•2,721.6= 5,987.52 lbs
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The graph of function g(x) is a transformation of the graph of function f(x) = x2.g(x) =
mariarad [96]

Given:

The graph of function g(x) is a transformation of the graph of function f(x) = x²

As shown: the graph of g(x) is open down

So, we will reflect f(x) over the x-axis, the function will be ⇒ -x²

And there is horizontal compression so, the factor of compression will be > 1

So, the function will be ⇒ -2x²

Finally, there is a vertical shift down 3 units

So,

g(x)=-2x^2-3

6 0
1 year ago
What is the inverse of the function f(x)=x+3
Valentin [98]

Hello,

The inverse of the function is f^-1(X)=-3-x

How?

f (x)=-x-3

replace f(X) with y

y=-x-3

interchange the variables

x=-y-3

solve for y and replace f^-1 (X)


Hope this helps


4 0
4 years ago
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Which property is used in the following expression ? (a x b) x c = a x (b x c)
Firlakuza [10]
A- Associative Property of Multiplication
4 0
3 years ago
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What will be the value of
madreJ [45]

The expression as given doesn't make much sense. I think you're trying to describe an infinitely nested radical. We can express this recursively by

\begin{cases}a_1=\sqrt{42}\\a_n=\sqrt{42+a_{n-1}}\end{cases}

Then you want to know the value of

\displaystyle\lim_{n\to\infty}a_n

if it exists.

To show the limit exists and that a_n converges to some limit, we can try showing that the sequence is bounded and monotonic.

Boundedness: It's true that a_1=\sqrt{42}\le\sqrt{49}=7. Suppose a_k\le 7. Then a_{k+1}=\sqrt{42+a_k}\le\sqrt{42+7}=7. So by induction, a_n is bounded above by 7 for all n.

Monontonicity: We have a_1=\sqrt{42} and a_2=\sqrt{42+\sqrt{42}}. It should be quite clear that a_2>a_1. Suppose a_k>a_{k-1}. Then a_{k+1}=\sqrt{42+a_k}>\sqrt{42+a_{k-1}}=a_k. So by induction, a_n is monotonically increasing.

Then because a_n is bounded above and strictly increasing, the limit exists. Call it L. Now,

\displaystyle\lim_{n\to\infty}a_n=\lim_{n\to\infty}a_{n-1}=L

\displaystyle\lim_{n\to\infty}a_n=\lim_{n\to\infty}\sqrt{42+a_{n-1}}=\sqrt{42+\lim_{n\to\infty}a_{n-1}}

\implies L=\sqrt{42+L}

Solve for L:

L^2=42+L\implies L^2-L-42=(L-7)(L+6)=0\implies L=7

We omit L=-6 because our analysis above showed that L must be positive.

So the value of the infinitely nested radical is 7.

4 0
3 years ago
$10,000 is invested at two different rates. $2,500 is invested at 4%, and the rest is invested at 5%. How much interest is earne
viva [34]
So, what we have to do is split 10000
0.04(2500) + 0.05(7500)
Multiply:
100 + 375 = 475
$475 is made in one year
6 0
4 years ago
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