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3 years ago

PLEASE HELP!!! HSJSHGXDBSJHCBDSHDCB PLEASEE

Mathematics

2 answers:

KatRina [158]3 years ago

7 0

Answer:

the answer is 30

............................

djyliett [7]3 years ago

6 0

Answer:

you can give her brainliest now c:

Step-by-step explanation:

You might be interested in

Find r(t) if r'(t) = 5t4i + 6t5j + t k and r(1) = i + j.

Vladimir [108]

$\mathbf r(t)=\displaystyle\int(5t^4\,\mathbf i+6t^5\,\mathbf j+t\,\mathbf k)\,\mathrm dt$
$\mathbf r(t)=(t^5+C_1)\,\mathbf i+(t^6+C_2)\,\mathbf j+\left(\dfrac12t^2+C_3\right)\,\mathbf k$

Given $\mathbf r(1)=\mathbf i+\mathbf j$ , we have

$\begin{cases}1^5+C_1=1\\\\1^6+C_2=1\\\\\dfrac121^2+C_3=0\end{cases}\implies C_1=0,C_2=0,C_3=-\dfrac12$

so that the particular solution is

$\mathbf r(t)=t^5\,\mathbf i+t^6\,\mathbf j+\dfrac12(t^2-1)\,\mathbf k$

8 0

3 years ago

A circle has a diameter of 4 inches. A square has a side length of 4 inches. What is true about the areas of these two figures?

liubo4ka [24]

Answer:

The area of the square is greater than the area of the circle.

8 0

3 years ago

Help plz I beg you plz

zzz [600]

20 is the answer to this problem

6 0

3 years ago

It’s late work and I’ve forgotten how to do it

Veseljchak [2.6K]

You want to eliminate one of the terms (x or y) in one of the equations so you can solve for the other variable. You have to multiply by the opposite number of the coefficient to be able to eliminate the term in the other equation. If the x coefficient is 2, then you have to multiply the entire other equation by -2. If the y coefficient is -5, then you have to multiply the entire other equation by 5.

10)
-4x + 9y= 9
x - 3y= -6

STEP 1:
multiply the bottom equation by 4
4(x- 3y)= 4(-6)
4x - 12y= -24

STEP 2:
add the top equation and the equation from step 2

-4x + 9y= 9
4x - 12y= -24
the x term cancels out

-3y= 15
divide both sides by -3

y= -5

STEP 2:
substitute the y value in either original equation to solve for x

x - 3y= -6
x - 3(-5)= -6

x + 15= -6
subtract 15 from both sides

x= -21

ANSWER: x= -21; y= -5
____________________

12)
-7x + y= -19
-2x + 3y= -19

STEP 1:
multiply the top equation by -3 to eliminate the y term and to solve for x

-3(-7x + y)= -3(-19)
21x - 3y= 57

STEP 2:
add the bottom equation and the equation from step 2 to solve for x

-2x + 3y= -19
21x - 3y= 57
the y term cancels out

19x= 38
divide both sides by 19

x= 2

STEP 3:
substitute the x value in step 2 to solve for y; you can use either original equation

-7x + y= -19
-7(2) + y= -19

-14 + y= -19
add 14 to both sides

y= -5

ANSWER: x= 2; y=-5

Hope this helps! :)

4 0

3 years ago

Eth enlarged the triangle below by a scale of 5.

levacccp [35]

Answer:

She should have multiplied one half (4)(3.5) by 5 squared.

Step-by-step explanation:

We are given that

Base of triangle=b=4 cm

Height of triangle=h=3.5 cm

Area of triangle= $\frac{1}{2}bh=\frac{1}{2}(4)(3.5) cm^2$

After enlarged

Scale factor=5

New base of enlarged triangle=b'=4(5) cm

Height of enlarged triangle=h'=3.5(5) cm

Area of enlarged triangle= $\frac{1}{2}4(5)(3.5\times 5)=\frac{1}{2}(4)(3.5)(5^2) cm^2$

But Beth wrote

Area of enlarged triangle= $\frac{1}{2}(4)(3.5)(5)=35 cm^2$

She should have multiplied one half (4)(3.5) by 5 squared.

3 0

3 years ago